Question

Solve 6x^2 +5x - 4 = 0 by factoring. Enter each step. please help me.

Answer 1

Answer:

$\frac{1}{2}$ and $-\frac{4}{3}$

Step-by-step explanation:

We can solve this equation using the quadratic formula, which is

$\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}$

Assuming that with your equation, 6x² + 5x - 4 = 0, a is 6, b is 5, and c is -4.

We can substitute inside the equation.

$\frac{{ - 5 \pm \sqrt {5^2 - 4 \cdot 6\cdot\-4} }}{{2 \cdot6}}}$

$\frac{{ - 5 \pm \sqrt {25 + 96} }}{{12}}}$

$\frac{{ - 5 \pm \sqrt {121} }}{{12}}}$

$\frac{{ - 5 \pm 11 }}{{12}}}$

Now, we can find our two values by using subtraction/addition and division.

$-5 + 11 = 6\\-5 - 11 = -16$

$\frac{6}{12} =\frac{1}{2} \\-\frac{6}{12} =-\frac{4}{3}$

I hope this helped!

Answer 2

Answer:

x = -4/3    x =1/2

Step-by-step explanation:

6x^2 +5x - 4 = 0

6 has factors of 3 and 2   and 6 and 1

4 has factors of -4 and 1  and -2 and 2, and -1 and 4

We want +5 in the middle

3* -1 + 4*2 = 5

( 3x+4) ( 2x -1) =0

Using the zero product property

3x+4 =0   2x-1 =0

3x = -4    2x =1

x = -4/3    x =1/2