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3 years ago

14

Bianca puts $10 in a savings account each month and an extra $20 when she receives money for her birthda If her birthday was thi

s week, which expression represents the amount she has saved this year

1 answer:

german3 years ago

8 0

The expression should look something like 10x+20.

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Find the distance between the points (3 4) and (4 3)

Usimov [2.4K]

Answer:

$\sqrt{2}$ or 1.414213

Step-by-step explanation:

Use the distance formula to determine the distance between the two points.

$d = \sqrt{(x_{2} -x_{1})^{2} + (y_{2} - x_{1})^{2} }$

d = distance

$(x_{1}, y_{1})$ = coordinates of the first point

$(x_{2}, y_{2})$ = coordinates of the second point

8 0

3 years ago

Drag the numbers below to put them in order from least to greatest:<br> -3 4 1 -4 -12 -6

Kisachek [45]

Answer:

it is -12, -6, -4, -3, 1, 4

8 0

2 years ago

Read 2 more answers

Need math help!!!!!!!!!!!!!!!!!!!!!!!!!

frutty [35]

Well we need to follow PEMDAS. Parentheses, Exponents, Multiplication, Division, Addition, Subtraction. The "X" is in the Exponents place. Therefore we would take 10 X 5.5 first. Which equals 55. Then you have to take it times 1. So the answer to the first one is 55. Then with the next one, you do the same steps, except at the end, your exponent is 2. So you would take 55 times 55 and get 3,025. So the answer to your second one is 3,025. Hope this is correct and hope this helps!

-Twix

5 0

3 years ago

Automobile policies are separated into two groups: low-risk and high-risk. Actuary Rahul examines low-risk policies, continuing

jeka57 [31]

Answer:

The probability that Actuary Rahul examines fewer policies than Actuary Toby is 0.2857.

Step-by-step explanation:

It is provided that the automobile policies are separated into two groups: low-risk and high-risk. Actuary Rahul examines low-risk policies, continuing until a policy with a claim is found and then stopping. Actuary Toby follows the same procedure with high-risk policies.

The probability that a low-risk policy has a claim is, P (L) = 0.10.

The probability that a high-risk policy has a claim is, P (H) = 0.20.

For positive integer <em>n</em>, the probability that Actuary Rahul examines exactly <em>n</em> policies is:

P (Actuary Rahul examines exactly <em>n</em> policies) = $(1-0.10)^{n-1} \times0.10$

$=0.90^{n-1}\times 0.10$

The probability that Actuary Toby examines more than <em>n</em> policies is:

P (Actuary Toby examines more than <em>n</em> policies) = $(1-0.20)^{n}$

$=0.80^{n}$

It is provided that the claim statuses of policies are mutually independent.

Compute the probability that Actuary Toby examines more policies than Actuary Rahul as follows:

$P(\text{Toby}>\text{Rahul})=\sum\limits^{\infty}_{n=1}{(0.90^{n-1}\times 0.10)\times 0.80^{n}}$

$=\frac{0.10}{0.90}\sum\limits^{\infty}_{n=1}{0.90^{n}\times 0.80^{n}}\\\\=0.1111\times \sum\limits^{\infty}_{n=1}{0.72^{n}}\\\\=0.1111\times \frac{0.72}{1-0.72}\\\\=0.285686\\\\\approx 0.2857$

Thus, the probability that Actuary Rahul examines fewer policies than Actuary Toby is 0.2857.

4 0

3 years ago

629,999 rounded to the nearest ten thousand

Elis [28]

It is 630,000
hope I helped:)

8 0

3 years ago