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expeople1 [14]
3 years ago
8

How to solve (x+2) (x-3) = 0

Mathematics
1 answer:
suter [353]3 years ago
3 0
Using the FOIL (First, Outside, Inner, Last) method, you multiply the two parenthesis together. First, you multiply x • x which = x^2, then outside, x • -3 = -3x. Next you multiply the inner number and variable, 2 • x = 2x, and finally the last values, 2 • -3 = -6. Then add all the values together (x^2 - 3x + 2x - 6) which equals the final answer x^2 - x - 6 :) Im not great at explaining but I hope this helps
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