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IgorC [24]
4 years ago
9

What is the difference between an approximate answer and exact answer

Mathematics
2 answers:
ASHA 777 [7]4 years ago
5 0
An example would be  1/3  as an exact answer  and 0.33 as an approximate answer because 1/3 = 0.333.....  - a recurring decimal where there are an infinite number of 3's. 0.33 would be correct to the nearest hundredth.

Radicals are exact answers :- like  √2 , √5 .  Approximate value for √2 is 1.414
Brilliant_brown [7]4 years ago
3 0
Approximate means about, and exact means, spot on, not approximate, like the exact answer of 3+3 is 6 hope it helps!!
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3 years ago
Solution to this inequality. 72≥b+95
Olegator [25]

Answer:

b≤-23

Step-by-step explanation:

72≥b+95   Move terms

-b≥95-72   subtract

-b≥23

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Who is Peeta traveling with immediately after the first battle?
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The girl who made a fire underneath Katniss.

Step-by-step explanation:

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Hope this helps :)

8 0
3 years ago
What is the 79th term of this arithmetic sequence? 3, 9, 15, 21,
hodyreva [135]
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5 0
3 years ago
: Use The TI Calculator To Answer The Question. Find The Probability That A Z-score Will Be Between 0.7 And 1.4. A) 0.242 O B) 0
ZanzabumX [31]

Answer:

P(0.7

And we can find this probability with the following difference:

P(0.7

We can use the following commands on the ti 84

2nd>VARS>DISTR

And then we look for normalcdf and we input this:

normalcdf(0.7,1.4,0,1)

The other possible code would be:

normalcdf(-1000,1,4,0,1)-normalcdf(-1000,0.7,0,1)

And we got:

P(0.7

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

For this case we want to find this probability:

P(0.7

And we can find this probability with the following difference:

P(0.7

We can use the following commands on the ti 84

2nd>VARS>DISTR

And then we look for normalcdf and we input this:

normalcdf(0.7,1.4,0,1)

The other possible code would be:

normalcdf(-1000,1,4,0,1)-normalcdf(-1000,0.7,0,1)

And we got:

P(0.7

3 0
3 years ago
Read 2 more answers
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