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JulijaS [17]
3 years ago
6

If my friend gives me $1 to buy candy how much would I pay her back?

Mathematics
1 answer:
ANTONII [103]3 years ago
7 0
If your friend gave you $1 you would most likely only need to pay her back $1 unless you're talking about interest.
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Mallanie 2 years older then Bill . Bill is 27 years old
dlinn [17]

really?, 27+2=29, 29 is youre answer.

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4 years ago
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Nate and his sister Natalie are walking around the track at school and they’re walking at a steady rate. Nate walks 5 feet in 2
lutik1710 [3]
 Nate     Natalie
  5_2        2_2
10_4        4_4
15_6        6_6

Natalie walked 6 feet
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3 years ago
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Solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations.
hram777 [196]

Write the system in augmented-matrix form:

\left[\begin{array}{ccc|c}2&2&4&16\\5&-2&3&-1\\1&2&-3&-9\end{array}\right]

Multiply through row 1 by 1/2:

\left[\begin{array}{ccc|c}1&1&2&8\\5&-2&3&-1\\1&2&-3&-9\end{array}\right]

Add -1(row 1) to row 3, and add -5(row 1) to row 2:

\left[\begin{array}{ccc|c}1&1&2&8\\0&-7&-7&-41\\0&1&-5&-17\end{array}\right]

Swap rows 2 and 3:

\left[\begin{array}{ccc|c}1&1&2&8\\0&1&-5&-17\\0&-7&-7&-41\end{array}\right]

Add -7(row 2) to row 3:

\left[\begin{array}{ccc|c}1&1&2&8\\0&1&-5&-17\\0&0&-42&-160\end{array}\right]

Multiply through row 3 by -1/42:

\left[\begin{array}{ccc|c}1&1&2&8\\0&1&-5&-17\\0&0&1&\frac{80}{21}\end{array}\right]

Add 5(row 3) to row 2:

\left[\begin{array}{ccc|c}1&1&2&8\\0&1&0&\frac{43}{21}\\0&0&1&\frac{80}{21}\end{array}\right]

Add -1(row 2) and -2(row3) to row 1:

\left[\begin{array}{ccc|c}1&0&0&-\frac53\\0&1&0&\frac{43}{21}\\0&0&1&\frac{80}{21}\end{array}\right]

So the solution to the system is

x=-\dfrac53,y=\dfrac{43}{21},z=\dfrac{80}{21}

7 0
4 years ago
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A coin is tossed 4 times. what is the probability of getting heads each time
zimovet [89]

answer: 1/16

If you flip a coin 4 times, the probability of getting all heads is 1/16.

7 0
2 years ago
Factor:<br><br> 4b2−12b+9<br><br> A) (2b−3)2<br> B) (2b+3)2<br> C) (2b−3)(2b+3)<br> D) (2b−9)(2b−1)
tatuchka [14]

Answer:

A

Step-by-step explanation:

(2b-3)^2 = (2b-3)(2b-3) = 4b^2-12b+9

7 0
3 years ago
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