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Paladinen [302]
3 years ago
13

If f(x) is a linear function, what is the value of n?

Mathematics
2 answers:
lana [24]3 years ago
4 0
The generic equation for a linear function can be expressed in the slope intercept form f(x) = mx + b, where m is the slope and b is the y intercept. For this problem we can first find the equation of the line. Then we substitute x = 7 to get the f(x) value, which is n at the point x = 7.

To find the equation of the linear function we first find the slope. Slope is defined as the change in f(x) divided by the change in x. As we are given a linear function, the slope at every point is the same. We can pick any two points known to find the slope.

Let's pick (3, 7) and (9, 16). The slope m is m = (16-7)/(9-3) = 9/6 = 3/2.

Now that we have the slope, we can plug in the slope and one of the points to find b. Let's use the point (3, 7).
f(x) = mx + b
7 = (1/2)(3) + b
b = 11/2

Now we can write the equation
f(x) = (1/2)x + 11/2

Plugging in x = 7 we find that f(7) = 9. n = 9
Tju [1.3M]3 years ago
4 0

Answer:

Option C. 13

Step-by-step explanation:

Since f(x) is a linear function then we can rewrite the function in the form of an equation y = mx + c

where m is the slope of a line.

Since line passes through two points (3, 7), (9, 16)

Therefore m = (16 - 7)/(9 - 3) = 9/6 = 3/2

Now we know a point (16, 26.5) also lie on the line so by putting the values of m, x, and y in the equation.

y = 3x/2 + c

26.5 = 3×16/2 + c

c = 26.5 - 24 = 2.5

So the equation is y = 3x/2 + 5/2

y = 1/2(3x + 5)

If a point (7, n) lies on the line then

n = 1/2(3×7 + 5) = 1/2(21 + 5) = 26/2 = 13

Therefore n = 13 is the answer.

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EastWind [94]

Answer:

4. 21

5. 32

Step-by-step explanation:

First question:

sin(x) = opp/hyp = 22/63 = 0.3492

x = sin⁻¹(0.3492)

20.43. Rounded to the nearest degree, it would be 21.

Second question:

sin(x) = opp/hyp = 18/34 = 0.5294

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Let me know if you have any problems.

3 0
3 years ago
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Katen [24]

Answer:

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6 0
3 years ago
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GarryVolchara [31]

Answer:

Step-by-step explanation:

We have to solve the given expression,

\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y}

\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y} = \frac{-y(-9+33y+3y^3)}{100-49y^2}.\frac{7y^2+17y+10}{14y(y+2)}

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                                   = \frac{3(3-11y-y^3)(y+1)}{(10-7y)(14(y+2)}

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