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Paladinen [302]
3 years ago
13

If f(x) is a linear function, what is the value of n?

Mathematics
2 answers:
lana [24]3 years ago
4 0
The generic equation for a linear function can be expressed in the slope intercept form f(x) = mx + b, where m is the slope and b is the y intercept. For this problem we can first find the equation of the line. Then we substitute x = 7 to get the f(x) value, which is n at the point x = 7.

To find the equation of the linear function we first find the slope. Slope is defined as the change in f(x) divided by the change in x. As we are given a linear function, the slope at every point is the same. We can pick any two points known to find the slope.

Let's pick (3, 7) and (9, 16). The slope m is m = (16-7)/(9-3) = 9/6 = 3/2.

Now that we have the slope, we can plug in the slope and one of the points to find b. Let's use the point (3, 7).
f(x) = mx + b
7 = (1/2)(3) + b
b = 11/2

Now we can write the equation
f(x) = (1/2)x + 11/2

Plugging in x = 7 we find that f(7) = 9. n = 9
Tju [1.3M]3 years ago
4 0

Answer:

Option C. 13

Step-by-step explanation:

Since f(x) is a linear function then we can rewrite the function in the form of an equation y = mx + c

where m is the slope of a line.

Since line passes through two points (3, 7), (9, 16)

Therefore m = (16 - 7)/(9 - 3) = 9/6 = 3/2

Now we know a point (16, 26.5) also lie on the line so by putting the values of m, x, and y in the equation.

y = 3x/2 + c

26.5 = 3×16/2 + c

c = 26.5 - 24 = 2.5

So the equation is y = 3x/2 + 5/2

y = 1/2(3x + 5)

If a point (7, n) lies on the line then

n = 1/2(3×7 + 5) = 1/2(21 + 5) = 26/2 = 13

Therefore n = 13 is the answer.

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Below are tabulated a number of Rockwell G hardness values that were measured on a single steel specimen. Compute
Mashcka [7]

Answer:

a) 48.408

b) 1.235

Step-by-step explanation:

a)

The average hardness value xbar can be computed as

xbar=sum of values/number of values

xbar=(46.5+46.9+49.4+50.3+49.8+48.8+47+47.7+48.3+49.4+47.8+49)/12

xbar=580.9/12

xbar=48.408 (rounded to 3 decimal places).

The average hardness value is 48.408.

b)

The standard deviation hardness value s can be computed as

s=\sqrt{\frac{sum(x-xbar)^2}{n-1} }

x              x-xbar  (x-xbar) ²

46.5  -1.90833 3.64174

46.9  -1.50833 2.27507

49.4    0.99167 0.98340

50.3     1.89167 3.57840

49.8     1.39167 1.93674

48.8    0.39167 0.15340

47.0           -1.40833 1.98340

47.7   -0.70833 0.50174

48.3           -0.10833 0.01174

49.4    0.99167  0.98340

47.8           -0.60833 0.37007

49.0    0.59167 0.35007

Total                               16.7692

s=\sqrt{\frac{16.7692}{12-1} }

s=\sqrt{\frac{16.7692}{11} }

s=\sqrt{1.5245}

s=1.2347

s=1.235 (rounded to 3 decimal places)

The standard deviation hardness value is 1.235.

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Step-by-step explanation:

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Marrrta [24]

Answer:

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Step-by-step explanation:

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The given sequence has an initial term of a[1]=8 and a common ratio of 4/8=1/2. Then the general term is ...

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