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3 years ago

Can somebody explain to me what I need to do for this?

Mathematics

1 answer:

andrezito [222]3 years ago

4 0

Answer:

Im pretty sure that you just have to find the value of X and Y...

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1234567890+456789o0=

kondor19780726 [428]

Answer:

1,280,246,790 is the answer

4 0

3 years ago

Read 2 more answers

Help me pls. I need help with the question

likoan [24]

Answer:

$173.90

Step-by-step explanation:

The most obvious way to answer this question is to multiply $9.40 by 18.5

This would result in 173.90.

But I realize nobody like to deal with decimals in a multiplication problem, so here's the way I would do it (<em>especially if you don't have a calculator!</em>)

The strategy is to break it down!

Multiply $9.40 x 18 hours to start, since this is easier.

$9.4 x 18 = 169.2$

So, that's $169.20 for 18 hours of work.

We aren't finished, because Abdel worked for 18.5 hours.

So, what half of $9.40?

$9.4 / 2$

= 4.7

-or-

$4.70

So, knowing that Abdel makes $4.70 in half an hour, lets just add that onto the $169.20 we got earlier.

169.2 + 4.7 = 173.9

-or-

$173.90 for 18.5 hours of work!

8 0

3 years ago

Please please helppp answer correctly !!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!

marusya05 [52]

Answer:

holy.... that's a lot of variables.

4t+2s+w+u+x+v

4 0

3 years ago

A law firm is going to designate associates and partners to a big new case. The daily rate charged to the client for each associ

Semenov [28]

Answer:

$8700

Step-by-step explanation:

Associates cost $800 each, you have 9 associates, so multiply 800 by 9 which gives you: $800x 9= $7200.

Partners cost $1500 each, you have 4 partners, so multiply 1500 by 4 which gives you: $1500x 4=$6000.

Then add the two together like this: $7200+$1500= $8700.

4 0

2 years ago

Read 2 more answers

Cos 4θ − cos 2θ = sin θ

hichkok12 [17]

$cos(4\theta) - cos(2\theta) = sin(\theta)$
$-2sin(\frac{4\theta + 2\theta}{2})sin(\frac{4\theta - 2\theta}{2}) = sin(\theta)$
$-2sin(\frac{6\theta}{2}sin\frac{2\theta}{2}) = sin(\theta)$
$-2sin(3\theta)sin(\theta) = sin(\theta)$
$\frac{-2sin(3\theta)sin(\theta)}{-2sin(\theta)} = \frac{sin(\theta)}{-2sin(\theta)}$
$sin(3\theta) = -\frac{1}{2}$
$sin^{-1}[sin(3\theta)] = sin^{-1}(-\frac{1}{2})$
$3\theta = -30$
$\frac{3\theta}{3} = \frac{-30}{3}$
$\theta = -10$

7 0

3 years ago