Y increases by 8 as x increases by 2 so the relationship is linear with slope 4. That is y=4x+c and 7=-20+c, so c=27.
The relationship seems to be y=4x+27. The only point to fit this equation is (1,31), Answer 3
Well if 1/16 costs $2 then you do 16*2 to find the cost of 16/16 aka 1 pound. 16*2=32 so the answer is x = 32.
Answer: The length of segments between this point and the vertices of greater base are
and 18.
Step-by-step explanation:
Let ABCD is the trapezoid, ( shown in below diagram)
In which AB is the greater base and AB = 18 DC= 11, AD= 3 and BC = 7
Let P is the point where The extended legs meet,
So, according to the question, we have to find out : AP and BP
In Δ APB and Δ DPC,
∠ DPC ≅ ∠APB ( reflexive)
∠ PDC ≅ ∠ PAB ( By alternative interior angle theorem)
And, ∠ PCD ≅ ∠ PBA ( By alternative interior angle theorem)
Therefore, By AAA similarity postulate,

Let, DP =x
⇒ 
⇒ 33 +11x = 18x
⇒ x = 33/7= 
Thus, PD= 
But, AP= PD + DA
AP= 
Now, let PC =y,
⇒ 
⇒ 77 + 11y = 18y
⇒ y = 77/7 = 11
Thus, PC= 11
But, PB= PC + CB
PB= 11+7 = 18
I am not sure but its might be .125