Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
The missing step 2 should be;
The quantity of the sum of thirty six plus two divided by 0.5 − 14.8 ÷ 8
The missing step 6 would be that; 76 - 1.85
<h3>How to Solve Mathematical Order of Operations?</h3>
We want to know the steps to solving the expression the quantity of the sum of six squared plus two divided by the absolute value of negative 0.5 − 14.8 ÷ 8
This can be expressed as;
6² + 2 ÷ |-0.5| - 14.8 ÷ 8
Thus, the next step which is step 2 should be;
The quantity of the sum of thirty six plus two divided by 0.5 − 14.8 ÷ 8
The missing step 6 would be that;
76 - 1.85
Read more about Order of Operations at; brainly.com/question/27529825
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You would use cross multiplication:
X/2,000 = 3/5
Multiply: 2,000*3= 6,000
Divide: 6,000/5
Answer: 1,200 doctors use brand x
Answer:
Figure A
Step-by-step explanation:
Hope it helps.
