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3 years ago

5

Josiah takes a multiple-choice quiz that has three questions. Each question has five answer options. If he randomly chooses his

answers, what is the probability that he will get all three correct?

2 answers:

ahrayia [7]3 years ago

6 0

The answer is 1/125.

k0ka [10]3 years ago

4 0

For E2020 users the answer is C (1/125)

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Find two numbers the quotient is between. 41÷3

Mnenie [13.5K]

The quotient between 41/3 is 13 to 14. Easy Division.

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4 years ago

Find the HCF of x³y² and x^2<br>

Elina [12.6K]

Answer:

$x^2$

Step-by-step explanation:

Hello!

The HCF or the highest common factor (sometimes also known as the greatest common factor, GCF), is the greatest factor between terms.

First, let's expand both terms:

$x^3y^2 = x*x*x*y*y$
$x^2 = x*x$

If we keep them on top of another, we can see that the overlapping variables are $x*x$ , meaning that the greatest common factor between them is $x^2$ .

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2 years ago

Sophia puts $250 in the bank with a 2.5% annual interest rate compounded monthly. If Sophia does not touch his money, how much m

Fittoniya [83]

Answer:

<h3> D) $276.26</h3>

Step-by-step explanation:

Deposited amount initially (P) = $250.

Rate of interest(r) = 2.5% compounded monthly = 0.025

Number of years (t) = 4.

Number of months in an year (n) = 12.

Formula for compound interest:

$A=P(1+\frac{r}{n})^{nt}$ .

Plugging values in formula, we get

$A= 250(1+\frac{0.025}{12})^{12\times 4}$

$A= 250(1.00208)^{48}$

$A= 250\times \:1.10506$

A=276.26.

<h3>Therefore, correct option is D) $276.26.</h3>

7 0

3 years ago

If a > b > c > d, then which is larger, a+c or b+d ? Can we tell from a > b > c > d which of a+d and b+c is la

victus00 [196]

Answer:

1. a+c is larger than b+d

2. No way to tell whether a+d or b+c is larger.

Step-by-step explanation:

<u>1. Which is larger, a+c or b+d?</u>

Let a, b, c, and d be any numbers such that $a > b > c > d$ .

Specifically, note that $a > b$ , and subtracting b from both sides of the inequality, observe that $a-b > 0$ .

Similarly, $c > d$ , and subtracting d from both sides of the inequality, observe that $c-d > 0$ .

From this, <u>add "a-b"</u> (a positive number, as proven above) to both sides of the inequality.

$(a-b)+(c-d) > (a-b)+0$

Addition by zero (<u>the additive identity</u>) doesn't change anything, so the right side remains "a-b"...

$(a-b)+(c-d) > a-b$

... and <u>"a-b" is positive</u>...

$(a-b)+(c-d) > a-b > 0$

... so, by the <u>transitive property</u> of inequality...

$(a-b)+(c-d) > 0$

Recall that <u>subtraction is addition by a negative</u> number...
$a+(-b)+c+(-d) > 0$

...and that <u>addition is associative and commutative</u>, so things can be added in any order, so the middle two terms on the left side can be rearranged...

$a+c+(-b)+(-d) > 0$

<u>Adding b + d</u> to both sides of the inequality

$(a+c+(-b)+(-d))+(b+d) > 0+(b+d)$

... and <u>simplifying</u>

$a+c > b+d$

So, a+c is larger than b+d.

<u>2. Which is larger, a+d or b+c?</u>

Consider the following two examples:

<u>Example 1</u>

Suppose a=10; b=3; c=2; d=1.

Note that $a > b > c > d$ ( $10 > 3 > 2 > 1$ ) and, also observe that $a+d=(10)+(1)=11$ , and $b+c=(3)+(2)=5$ , so a+d is larger than b+c.

<u>Example 2</u>

However, suppose a=10; b=9; c=8; d=1.

Note that $a > b > c > d$ ( $10 > 9 > 8 > 1$ ) but that $a+d=(10)+(1)=11$ , and $b+c=(9)+(8)=17$ , so a+d is smaller than b+c.

So, in one example, a+d is bigger, and in the other, a+d is smaller. Therefore, there is no way to tell which of a+d or b+c is larger from only the given information.

5 0

2 years ago

Multiply. (2x-1)(3x+5)

Nookie1986 [14]

ANSWER

6x² + 7x - 5

Step-by-step explanation:

(2x-1)(3x+5)

= 6x² + 10x - 3x - 5

= 6x² + 7x - 5

3 0

3 years ago

Read 2 more answers