Question

A

Answer 1

Answer:

$y=(x+2)(x-3)$

Step-by-step explanation:

Given: $y=x^2-x-6$

To find: a factored form of the given equation

Solution:

The equation $y=ax^2+bx+c$ can be written in factored form as $y=a(x-r_1)(x-r_2)$.

To find the x-intercepts, put $y=0$.

Graph of the equation $y=a(x-r_1)(x-r_2)$ represents a parabola.

$y=x^2-x-6\\=x^2+(-1)x-6\\=x^2+(-3+2)x-6\\=x^2-3x+2x-6\\=x(x-3)+2(x-3)\\=(x+2)(x-3)\\\Rightarrow y=(x+2)(x-3)$