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2 years ago

10

Help please. See photo

2 answers:

olganol [36]2 years ago

6 0

$\huge\sf\purple{}$

Option B

Dmitriy789 [7]2 years ago

3 0

Answer:

$\sqrt[3]{7}$

Step-by-step explanation:

$here \: the \: power \: of \: 7 \: is \: 3 \\ the \: cube \: represented \: by \: the \: radical \: sign \: with \: number \: 3 \\ \sqrt[3]{x} =cube \: root \: . \\ so \: we \: can \: write \: the \: given \: expression \ \: as \: \\ \: 7 \times \frac{1}{3} = \sqrt[3]{7} \\ thus \: \: the \: ans \: is \: a. \: \sqrt[3]{7}$

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So i dont know what 9+4+x is can you help?

Dahasolnce [82]

Answer:

13+x

Step-by-step explanation:

all you have to do is 9+4 which is 13 and leave the +x so you get 13+x as your answer

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3 years ago

Read 2 more answers

In the figure is a right triangle ABC with AC=10cm and BC=6cm. Determine: 1.5.1 The height AB (hint: Theorem of Pythagoras)

Alexxandr [17]

Answer:

height AB is 8 cm

Step-by-step explanation:

AB= √AC^2- BC^2

= √(10)^2- (6)^2

= √100-36

= √64

= 8

3 0

3 years ago

This isn't a math question. Hellooo!!! Can someone pls help me??? how does racial discrimination relate to economic statificatio

borishaifa [10]

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3 years ago

Pls solve the simultaneous equation in the attachment.

siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

$\frac{x}{2}-\frac{y}{5}=1$ ----> equation A

$y-\frac{x}{3}=8$ ----> equation B

Multiply equation A by 10 both sides to remove the fractions

$5x-2y=10$ ----> equation C

isolate the variable y in equation B

$y=\frac{x}{3}+8$ ----> equation D

we have the system of equations

$5x-2y=10$ ----> equation C

$y=\frac{x}{3}+8$ ----> equation D

Solve the system by substitution

substitute equation D in equation C

$5x-2(\frac{x}{3}+8)=10$

solve for x

$5x-\frac{2x}{3}-16=10$

Multiply by 3 both sides

$15x-2x-48=30$

$15x-2x=48+30$

Combine like terms

$13x=78$

$x=6$

<em>Find the value of y</em>

$y=\frac{x}{3}+8$

$y=\frac{6}{3}+8$

$y=10$

The solution is the ordered pair (6,10)

Part b) we have

$xy=21$ ---> equation A

$x+5y=22$ ----> equation B

isolate the variable x in the equation B

$x=22-5y$ ----> equation C

substitute equation C in equation A

$(22-5y)y=21$

solve for y

$22y-5y^2=21$

$5y^2-22y+21=0$

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

$x=22-5(1.4)=15$

For y=3

$x=22-5(3)=7$

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0

3 years ago

Jill and Erika made 5 gallons of lemonade for their lemonade stand.

julia-pushkina [17]

Part 1: 4 quarts in a gallon
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They will make $40.00

8 0

3 years ago