Answer:
(d) The functions are not inverses because for each ordered pair (x, y) for one function, there is no corresponding ordered pair (y, x) for the other function.
Step-by-step explanation:
If functions are represented by a table of ordered pairs, their inverse function is the set of ordered pairs with the x- and y-values swapped.
Here, for (x, y) = (0.75, 1038.18), the pair from the other table that begins to correspond is (y, x) = (0.75, 1057.81). These reversed pairs are not the same, so the functions are not inverses of each other.
_____
<em>Comment on the tables</em>
Table A is for a 5-year investment; table B is for a 7.5 year investment. They cannot be inverses of each other.
The given function is

The general form of the cosine function is

a is the amplitude
2pi/b is the period
c is the phase shift
d is the vertical shift
By comparing the two functions
a = 4
b = pi
c = 0
d = 1
Then its period is

The equation of the midline is

Since the maximum is at the greatest value of cos, which is 1, then

Since the minimum is at the smallest value of cos, which is -1, then

Then substitute them in the equation of the midline

The answers are:
Period = 2
Equation of the midline is y = 1
Maximum = 5
Minimum = -3
A. neither a function nor a relation