Please answer this !!<br>2x + 6 32°

A sculptor needs to lift a piece of marble. It is a cuboid with dimensions 1m by 0.6 m by 0.3 m. Marble has a density of 2.7 g/c

geniusboy [140]

P = m/v
To find the mass you have to do Density x Volume.
The volume of the cuboid is 0.18 m cubed and the density is 2.7g/cm cubed.
The 2.7 g/cm cubed must be converted into kg/m cubed to find the mass in kg. Which is 2,700 kg/ m cubed.
2,700 x 0.18 = 486 kg.
The mass of the marble in kg is 486kg

4 0

3 years ago

An automobile manufacturer has given its car a 52.6 miles/gallon (MPG) rating. An independent testing firm has been contracted t

Arte-miy333 [17]

Answer:

Null hypothesis: $\mu = 52.6$

Alternative hypothesis: $\mu \neq 52.6$

$z=\frac{52.8-52.6}{\frac{1.6}{\sqrt{250}}}=1.976$

$p_v =2*P(z>1.976)=0.0482$

Since the p value is lower than the significance level wedon't have enough evidence to conclude that the true mean is significantly different from 52.6 MPG.

Step-by-step explanation:

Information provided

$\bar X=52.8$ represent the sample mean for the MPG of the cars

$\sigma=1.6$ represent the population standard deviation

$n=250$ sample size of cars

$\mu_o =52.6$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test

Hypothesis

We need to conduct a hypothesis in order to check if the true mean of MPG is different from 52.6 MPG, the system of hypothesis would be:

Null hypothesis: $\mu = 52.6$

Alternative hypothesis: $\mu \neq 52.6$

Since we know the population deviation the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Calculate the statistic

Replacing we have this:

$z=\frac{52.8-52.6}{\frac{1.6}{\sqrt{250}}}=1.976$

Decision

Since is a two tailed test the p value would be:

$p_v =2*P(z>1.976)=0.0482$

Since the p value is lower than the significance level wedon't have enough evidence to conclude that the true mean is significantly different from 52.6 MPG.

3 0

3 years ago

Aquarius is an underwater ocean laboratory located in the Florida Keys National Marine Sanctuary. Solve the equation 31/25x=−62

poizon [28]

31/25X = -62, ⇒31 = -62* 25X ⇒ X = -31/(62*25), X= -31/ 1550

4 0

3 years ago

What is the exact volume of a sphere that has a radius of 7.5 ft?

Anettt [7]

The exact radius is
V
≈1767.15ft³

3 0

3 years ago

Read 2 more answers

Researchers wanted to study physical activity in children, so they gave 74 randomly chosen children a "FitBit" to recorded how m

luda_lava [24]

Answer:

Step-by-step explanation:

The estimated regression equation to predict the daily steps taken is:

Daily step= 6350.02 - 217.90BMI + 2702.12Grade_middle + 601.44BMI * Grade_middle

where Grade_middle=1 if the student is in middle school, and Grade_middle=0 if the student is in high school

b) The slope of BMI is -217.90. The negative value of the slope indicates that BMI and Daily steps taken move in opposite direction.

We can say that for 1 unit increase in the BMI, the predicted value of Daily Steps taken by the student decreases by 217.90, while keeping other variables unchanged.

c) The regression equation for middle school students can be obtained by setting Grade_middle=1

Daily step= 6350.02 - 217.90BMI + 2702.12 * 1 + 601.44BMI * 1

= 6350.02 - 217.90BMI + 2702.12 + 601.44BMI

= 9052.14 + 383.54BMI

Therefore, the slope of BMI on steps taken for students in middle school is 383.54

The regression equation for high school students can be obtained by setting Grade_middle=0

Daily Steps = 6350.02 - 217.90BMI + 2702.12 x 0 +601.44BMI*0 = 6350.02 - 217.90BMI

Therefore, the slope of BMI on steps taken for students in high school is -217.90

The model says that variables, the daily steps taken and the BMI of a middle school student are positively correlated (move in the same direction) and the daily steps taken and the BMI are negatively correlated (move in opposite direction) for a high school student. The above slopes say that for 1 unit increase in the BMI for students in middle school increases the predicted daily steps taken by 383.54 and for 1 unit increase in the BMI for students in high school decreases the predicted daily steps taken by 217.90

d) The predicted value of daily steps taken for a BMI=20 and Grade_middle=1 is

Daily Steps = 6350.02 – 217.90 x 20 + 2702.12 x1 +601.44 x 20 x 1 = 16722.94

The actual value of the daily steps taken by a middle school student with a BMI of 20 is 7000

The residual is calculated as

$\text{residual}=\text{Actual}-\text{predicted}=7000-16722.94=-9722.94$

Therefore, this student’s residual is -9722.94

7 0

3 years ago

Please answer this !!2x + 6 32°​

Please answer this !!2x + 6 32°