Ayuda me ( help me ) lol please tho
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Answer:
The probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.
Step-by-step explanation:
Let <em>X</em> = number of individuals in the United States who held multiple jobs.
The probability that an individual holds multiple jobs is, <em>p</em> = 0.13.
The sample of employed individuals selected is of size, <em>n</em> = 225.
An individual holding multiple jobs is independent of the others.
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 225 and <em>p</em> = 0.13.
But since the sample size is too large Normal approximation to Binomial can be used to define the distribution of proportion <em>p</em>.
Conditions of Normal approximation to Binomial are:
- np ≥ 10
- n (1 - p) ≥ 10
Check the conditions as follows:
The distribution of the proportion of individuals who hold multiple jobs is,
Compute the probability that less than 7.1% of the individuals in this sample hold multiple jobs as follows:
*Use a <em>z</em>-table.
Thus, the probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.
11 bottles are needed to fill a 16 liter jug
<em><u>Solution:</u></em>
Given that, there is a 16 liter jug
There are liters of bottle
<em><u>Let us first convert the mixed fraction to improper fraction</u></em>
Multiply the whole number part by the fraction's denominator.
Add that to the numerator.
Then write the result on top of the denominator.
Thus the bottle is of 1.5 liter
We have to find the number of 1.5 liter bottles needed to fill 16 liter jug
Divide 16 by 1.5 to get result
Thus 11 bottles are needed to fill a 16 liter jug