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Fittoniya [83]
3 years ago
6

The production of which substance by using cell technology allows scientists to make treatments that can target specific types o

f cancer cells? steroid hormones fat-soluble vitamins monoclonal antibodies complex proteins
Mathematics
2 answers:
shepuryov [24]3 years ago
8 0

Answer:

Antibodies.

Step-by-step explanation:

Hope this helped!

liberstina [14]3 years ago
5 0

Answer:

I would assume (C) monoclonal antibodies

Step-by-step explanation:

I may be wrong so don't take my word for it but I'd assume it would be C because cancer is the cloning of corrupt or destroyed cells so monoclonal antibodies would target the destroyed or corrupted cells and eliminate them. If I'm just being an idiot, let me know.

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The area of the trapezoid is A= 56
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2 years ago
Which of the following statements is not​ true? A. If the probability of an event occurring is​ 1.5, then it is certain that eve
yawa3891 [41]

Answer:

Therefore, we conclude that the statement in (A) is incorrect.

Step-by-step explanation:

We have the following sentences:

A) If the probability of an event occurring is​ 1.5, then it is certain that event will occur.  

B) If the probability of an event occurring is​ 0, then it is impossible for that event to occur.

We know that the range of probability of an event occurring is in the segment [0, 1]. In statement under (A), we have the probability that  is equal to 1.5.

Therefore, we conclude that the statement in (A) is incorrect.

8 0
3 years ago
Cameron ran 3.8 miles per every 1.9 miles that Samantha ran and if Samantha and 7.6 miles how far did Cameron run
bija089 [108]
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cross multiply
(1.9)(x) = (3.8)(7.6)
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8 0
3 years ago
What is the square root of four
xz_007 [3.2K]

Answer:

It is +2 or since (+2)*(+2 ) gives. If you think that it would be (-2) also then you are wrong because root of a positive rational number is always positive number.

Step-by-step explanation:

Let the square root of four be ‘k’.

Then we have

(4)^1/2=k

(Squaring both sides)

4=(k)^2

=>(k)^2–4=0

=>(k)^2-(2)^2=0

=>[k+2][k-2]=0 {since (a)^2-(b)^2=(a+b)(a-b)}

if product of two numbers is 0 then either of one must be zero.

If k+2=0 then k=-2

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From here we got two answers but -2 should be omitted because when we square an equation we add “root extra”which means that when we square an equation one root is added.

3 0
3 years ago
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