All categories

3 years ago

Write the solutions for the equation 3x+y=180°

Mathematics

2 answers:

Leto [7]3 years ago

5 0

3x+y=180
3.x=3 pois x é 1
3+177=180

Nadusha1986 [10]3 years ago

4 0

180/3x then you get you answer

You might be interested in

If a number is added to itself and the sum is multipled by 2 , the product is 4

Step2247 [10]

The number is 1

1 + 1 = 2

2(2) = 4

1 is your answer

hope this helps

8 0

2 years ago

Help with question 4 please

Juliette [100K]

Answer: y=5 x=11

abc=def

ab=de <b=<e

17y-8=12+13y 11x-4=117

-13y -13y +4 +4

4y-8=12 11/11x=121/11

+8 +8 x=11

4/4y=20/4

y=5

7 0

2 years ago

In place value the Relationship between 2,000 and 20 is how many times

Katen [24]

Answer:

100

Step-by-step explanation:

20 times 100 equals 2000

6 0

2 years ago

Roxanne has $80 in a savings account. The interest rate is 10%, compounded annually. To the nearest cent, how much will she have

finlep [7]

104 because 10% of 80 is 8 years meaning 8+8+8=24 add 24 to 80 and ur answer is 104

3 0

3 years ago

The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a

Anettt [7]

Answer:

1) The size of the colony after 4 days is 6553 mosquitoes

2) After $t = 4.9\ days$

Step-by-step explanation:

To answer this question you must use the growth formula

$N = N_0e ^ {kt}$

Where

$N_0$ is the initial population of mosquitoes = 1000

t is the time in days

k is the growth rate

N is the population according to the number of days

We know that when t = 1 and $N_0=1000$ then N = 1600

Then we use these values to find k.

$1600 = 1000e ^{k(1)}\\\\\frac{1600}{1000} = e ^ k\\\\ln(\frac{1600}{1000}) = k\\\\k = 0.47$

Now that we know k we can find the size of the colony after 4 days.

$N = 1000e ^ {0.47(4)}\\\\N = 6553\ mosquitoes$

To know how long it should take for the population to reach 10,000 mosquitoes we must do N = 10000 and solve for t.

$10000 = 1000e ^ {0.47t}\\\\10 = e ^ {0.47t}\\\\ln(10) = 0.47t\\\\t = \frac{ln(10)}{0.47}\\\\t = 4.9\ days$

6 0

2 years ago