It looks like it would have to be choice D.
Explanation: Pagination is number assignment to pages. Word wrap is when if a word is too long it is sent to the next line. Editing would not be a precise or accurate answer.
Answer:
The answer is "option B".
Explanation:
In the given code, four double variable "len1, len2, len3, and total" is declared, in which the first three variables accept some value, and in the total variable, we add those variable. In the next step, an integer variable minLength is defined, which converts the decimal value to an integer and adds the value that is "0.5". In this section, the code uses as an intended purpose but only if the total of 3 lengths is equivalent to or larger then 0.5, and wrong choices can be described as follows:
- In option A, It accepts the negative value, that's why it is wrong.
- Option C, Option D, and Option E all were wrong because the code segment is work as intended.
Answer:
C. Mean
Explanation:
Mean = (∑
)/N
Median = central values when data is sorted
Mode = most repeated value
Standard deviation = 
In standard deviation, formula you may see that deviation is being calculated from the mean (central location). But here we take square of the value before adding all of them.
But if we just take 
, it would be equal to zero.
<u>EXAMPLE</u>
Take 4, 9, 5 as data
mean = (4+9+5)/3 = 18/3 = 6
sum of deviations from mean = (4-6)+(9-6)+(5-6) = (-2)+(3)+(-1) = 0
Answer:
C or D
Explanation:
If he has previous experience, C might be better answer, otherwise, D is right.
not sure with my answer either lol
Answer:
boolean isEven = false;
if (x.length % 2 == 0)
isEven = true;
Comparable currentMax;
int currentMaxIndex;
for (int i = x.length - 1; i >= 1; i--)
{
currentMax = x[i];
currentMaxIndex = i;
for (int j = i - 1; j >= 0; j--)
{
if (((Comparable)currentMax).compareTo(x[j]) < 0)
{
currentMax = x[j];
currentMaxIndex = j;
}
}
x[currentMaxIndex] = x[i];
x[i] = currentMax;
}
Comparable a = null;
Comparable b = null;
if (isEven == true)
{
a = x[x.length/2];
b = x[(x.length/2) - 1];
if ((a).compareTo(b) > 0)
m = a;
else
m = b;
}
else
m = x[x.length/2];
