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3 years ago

Find the equations of the tangent lines to x2+y2=1 at x=0, x=1 and x=35.

1 answer:

4 0

Assuming the equation is x^2 + y^2 = 1, then that's a circle, with radius 1, centered on the origin [0,0].

So there are two tangents at x = 0. They are y = 1, and y = -1 (horizontal lines).

There is one tangent at x = 1. It is x = 1 (a vertical line).

There is no tangent at x = 35, because the original equation has no solution at x = 35.

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Answer:

$x\leq 25\\y\geq 10\\.50x + y\geq 30$

Step-by-step explanation:

It is given that,

Amy wants to sell at most 25 cookies ,

Let number of cookies be ' $x$ ' , then $x$ should be less than or equal to 25

Which is represented by $x\leq 25$ ,

Further,

Let number of sprites be ' $y$ ', then ' $y$ ' should be greater than or equal to 10

Which is represented by $y\geq 10$

Also,

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= $1.00\times y$

= $y$

Now, combining these two should be greater than or equal to $30

representing this through an equation,

$.50x+y\geq 30$

Thus the sysytem of equations is given as:

$x\leq 25\\y\geq 10\\.50x + y\geq 30$

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2 years ago

What are prime numbers

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Answer:

2, 3, 5, 7 and 11 are the first few prime numbers.

Step-by-step explanation:

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Answer:

x = log(y/4)/log(1.0256)
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Step-by-step explanation:

The question is asking you to solve ...

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You already did this using a constant for y. Do the same thing with y instead of the constant.

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log(y/4) = x·log(1.0256) . . . . . take logs

log(y/4)/log(1.0256) = x . . . . . divide by the coefficient of x

Now, you have a model for x in terms of y, which is what the question is asking for.

x = log(y/4)/log(1.0256) . . . . . . . exact expression

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