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klio [65]
3 years ago
5

Four students draw a design for a class flag. Each flag is black and white. Which designs have the same fractions of black and w

hite? Explain how you know.
Mathematics
1 answer:
Orlov [11]3 years ago
3 0
Where is the picture
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Need some help with these 2 math questions, They are related so best to finish one then work on the bisect. Thank you.
ElenaW [278]

Answer:

iyfohvvlcoyyfpuufpupfyofgogpugulglgulgug

4 0
2 years ago
Read 2 more answers
The shampoo Eva likes to use costs $6 for a 24-ounce bottle. The conditioner she likes to use costs $12 for a 30-ounce bottle. H
lutik1710 [3]

Answer:

0.15

Step-by-step explanation:

6 divided by 24 equals 0.25

12 divided by 30 equals 0.4

0.4 minus 0.25 is 0.15

8 0
3 years ago
chelsea takes the bus to school,but she walks home. the bus travels to the school at an average speed of 45 miles per hour. whil
jekas [21]
For this case, the first thing you should know is:
 d: v * t
 Where,
 d: distance
 v: speed
 t: time
 To go to school by bus we have:
 d = 45 * t
 To return from school we have:
 d = 2.5 * (1-t)
 how the distance is the same:45 * t = 2.5 * (1-t)
 Answer:
 the equation that will help find the time it takes chelsea to get to school on the bus is:
 45 * t = 2.5 * (1-t)
 Note: the equation will have one solution. 
4 0
3 years ago
AC = 6
lord [1]

Answer:

Dilate from center A by scale factor of 2, then reflect over line AC

Step-by-step explanation:

6 0
2 years ago
If a computer network has 60 switching nodes, in how many ways can 2 or 3 nodes fail?___________
notka56 [123]

Answer:

There are 35990 ways in which 2 or 3 nodes fail

Step-by-step explanation:

Given : A computer network has 60 switching nodes.

To Find : In how many ways can 2 or 3 nodes fail?

Solution:

We are supposed to find no. of ways can 2 or 3 nodes fail.

So, we will use combination here .

No. of ways can 2 or 3 nodes fail=^{60}{C_2 +^{60}C_3

Formula : ^nC_r =\frac{n!}{r!(n-r)!}

No. of ways can 2 or 3 nodes fail=\frac{60!}{2!(60-2)!}+\frac{60!}{3!(60-3)!}

                                                       =35990

Hence there are 35990 ways in which 2 or 3 nodes fail

5 0
3 years ago
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