Let "b" represent the number of biscuits Jacky baked.
.. container A holds (3/7)b
.. container B holds (1 -3/7)*(5/8)b = (5/14)b
.. container C holds (1 -3/7 -5/14)b = (3/14)b = 168
Then
.. b = 168/(3/14) = 784
Jacky baked 784 biscuits.
cot(<em>θ</em>) = cos(<em>θ</em>)/sin(<em>θ</em>)
So if both cot(<em>θ</em>) and cos(<em>θ</em>) are negative, that means sin(<em>θ</em>) must be positive.
Recall that
cot²(<em>θ</em>) + 1 = csc²(<em>θ</em>) = 1/sin²(<em>θ</em>)
so that
sin²(<em>θ</em>) = 1/(cot²(<em>θ</em>) + 1)
sin(<em>θ</em>) = 1 / √(cot²(<em>θ</em>) + 1)
Plug in cot(<em>θ</em>) = -2 and solve for sin(<em>θ</em>) :
sin(<em>θ</em>) = 1 / √((-2)² + 1)
sin(<em>θ</em>) = 1/√(5)
.38 is greater because 3/10 is .30 and .38 is greater
Answer:
Square the binomial :)
Step-by-step explanation:
A bag contains 10 tiles with the letters A, B, C, D, E, F, G, H, I, and J. Five tiles are chosen, one at a time, and placed in a
lora16 [44]
I assume in this item, we are to find at which step is the mistake done for the calculation of the unknown probability.
For the possible number of arrangement of letter, n(S), the basic principles of counting should be used.
= 10 x 9 x 8 x 7 x 6 = 30,240
This is similar as to what was done in Meghan's work.
For the five tiles to spell out FACED, there is only one (1) possibility.
Therefore, the probability should be equal to 1/30,240 instead of the 1/252 which was presented in the steps above.
