The length of missing sides x = 5 units and y = 5 units.
<h3>What is Trigonometric ratios?</h3><h3>The six trigonometric ratios are sine (sin), cosine (cos), tangent (tan), cotangent (cot), cosecant (cosec), and secant (sec).</h3>
In ΔABC,
AB (Base) = y , BC(Hypotenuse) = 
, CA (perpendicular) = x
and ∠ABC = 
Now,
tan = perp. / base
1 = x /y
x= y .................(i)
again,
sin = perp. / Hypo.
x = 5
put in equation (i), we get
y = 5
Thus, the length of missing side of the given triangle is x = 5 units and y = 5 units.
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Well if you are given the radius, you can solve for it. As the volume of a cylinder is area of the base which is a circle times it height.
B • h = Pi r ^2 • h = 392 cm^3.
H = 392/Pi r^2.
This is the height or length.
Answer:
1 I think but you said they all have the same area
Answer:
<h2>36b + 60c</h2>
Step-by-step explanation:
Put a = 6 to the expression 2a(3b + 5c):
(2)(6)(3b + 5c) = 12(3b + 5c) <em>use the distributive property</em>
= (12)(3b) + (12)(5c) = 36b + 60c
