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Lady_Fox [76]
3 years ago
6

Is 6r and -15r like terms?

Mathematics
1 answer:
lions [1.4K]3 years ago
7 0
Yes, as long as thy have the same variable. In this case 6r-15r would be -9r
You might be interested in
Solve the system of equations by substitution.<br><br> y= -x-2<br> 3x+3y=6
Orlov [11]
Substitute -x-2 for y in 3x+3y=6
3x+3y=6
3x+3(-x-2)=6
-6=6 (Simplify both sides of the equation)
-6+6=6+6 ( add six to both sides)
0=12

Answer: No Solutions

Hope this helped

8 0
2 years ago
Read 2 more answers
Multiply (2 – 7i)(–1 + 4i).
azamat
(2 - 7i)(-1 + 4i)=-2+8i+7i+28=26+15i
5 0
3 years ago
Can someone plz help me !!!
egoroff_w [7]

Answer:

53! good luck and stay safe<3

8 0
3 years ago
two airplanes are flying in the air at the same height: airplane a is flying east at $$ mi/h and airplane b is flying north at $
olga55 [171]

The distance between the airplanes changing is  -390.

<h3>Calculation:</h3>

The miles from the airport to Airplane A can be calculated as follows: a = 30 -250t, where t is in hours.

<h3>Similar to airplane A, airplane B's distance from the airport can be expressed as...</h3>

b = 40 -300t

Using the Pythagorean theorem, one can calculate the separation (d) between the aircraft:

d^2 = a^2 + b^2

<h3>Depending on the passage of time, we have...</h3>

2dd' = 2aa' + 2bb', and d' = (aa' + bb')/d.

<h3>The values of its variables at t=0 must be determined in order to determine the numerical value of this</h3>

a = 30 -2500 = 30 a' = -250 b = 40 -3000 = 40 b' = -300

d = √(a²+b²) = √(900+1600) = 50

Then, d' = (30(-250) +40(-300))/50 = -19500/50 = -390

At a speed of 390 miles per hour, the space between the aircraft is closing.

<h3>How far apart are the equation's two planes?</h3>

The distance between the two planes is going to be the square root of six, therefore if we solve for d, multiply both sides of this equation by the square root of six, we obtain six is equal to negative d, or d is equal to negative six.

<h3>How widely apart are commercial airplanes?</h3>

For a commercial airliner, separation will typically be at least 3 miles laterally or 1,000 feet vertically (as stated in the question). The 5 mile rule is applied laterally in the enroute environment, at greater operating speeds over 10,000 feet, depending on the kind of radar and distance from the antennae.

To know more about Distance visit:-

brainly.com/question/15172156

#SPJ4

4 0
1 year ago
Help please!<br> 6x^2+2x-9=0<br> A 6.4, -8.4<br> B 1.1, -1.4<br> C -2.2, 2.8<br> D -1.1, -1.4
Yakvenalex [24]
6x^2+2x-9=0\\\\a=6;\ b=2;\ c=-9\\\\\Delta=b^2-4ac\to\Delta=2^2-4\cdot6\cdot(-9)=220\\\\x_1=\dfrac{-b-\sqrt\Delta}{2a};\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\x_1=\dfrac{-2-\sqrt{220}}{2\cdot6}=\dfrac{-2-\sqrt{220}}{12}\approx-1.4\\\\x_2=\dfrac{-2+\sqrt{220}}{2\cdot6}=\dfrac{-2+\sqrt{220}}{12}\approx1.1

Answer: B. 1.1; -1.4.
6 0
3 years ago
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