On a coordinate plane (-9, 2) and (-9, 10) are placed how many spot are inbetween the two

1 answer:

kramer3 years ago

6 0

They both share the same x coordinate, meaning there is a undefined slope. So it's basically a vertical line on the X value, -9. One y value is 10 and the other two, so all you have to do is 10-2 which gives you 8.
8 spots inbetween.

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How to solve x+3y=3 and 2x-3y=-12

Sever21 [200]

Get x on one side then you can use substitution
So, change x+3y=3 to x= -3y+3
Then plug in x to other equation to find y
2(-3y +3)-3y=-12
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Divide both sides by negative nine to find y
y = 2
Then plug in to original equation to find x
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Fine the equation of the line that is perpendicular to the given line and passes through the given point. Enter the right side o

Kipish [7]

Answer:

$y=-\frac{4}{7} x+\frac{55}{7}$

Step-by-step explanation:

Change the given equation to slope-intercept to get $y=\frac{7}{4}x-\frac{1}{4}$ . When you multiply the slopes of perpendicular lines, you get -1. -1 divided by $\frac{7}{4}$ is $-\frac{4}{7}$ . The slope of the new line is then $-\frac{4}{7}$ . The perpendicular line passes through (5, 5) so you can have the equation $5=-\frac{4}{7} (5)+b$ . Simplifying gets $b = \frac{55}{7}$ . So now the final equation for the perpendicular line is $y=-\frac{4}{7} x+\frac{55}{7}$