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3 years ago

What would the unit rates be for a man who walked 20 mi in 5 h?

Mathematics

2 answers:

user100 [1]3 years ago

6 0

$\frac{5}{20} \frac{h}{mi} = .25 \frac{h}{mi}$

Hope that helps

sergey [27]3 years ago

3 0

4 mile would be the unit rate of the man

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What is the y-intercept of f(x) = (-1/4)^x?

Elena-2011 [213]

Answer:

The correct answer is A.

To find the y-intercept, substitute in 0 for x and solve for y .

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3 years ago

PLEASE HURRY!! simplify completely show all work for full credit

Irina18 [472]

Answer:

$4x^{3}$

Step-by-step explanation:

Given:

$(\frac{192x^{12}}{3x^{3}} )^{\frac{1}{3}}$

Apply exponent rule of distribution:

$\frac{(192x^{12})^{\frac{1}{3}}}{(3x^{3})^{\frac{1}{3}}}$

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$\\\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{(3x^{3})^{\frac{1}{3}}}$

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$\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{3^\frac{1}{3}x}}$

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-> To explain this party since it is a bigger jump, $3^{\frac{1}{3}}x$ is on the top and the bottom, so it becomes a one. We are left with a four on the top, and using properties of exponents 4 - 1 = 3, explaining why we have $x^{3}$ leftover too.

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I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

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3 0

3 years ago

One month, ruby worked for 6 hours more than isaac, and svetlana worked 4 times as many hours as ruby. Together they worked 126

Anastasy [175]

Ruby worked 22 hours

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3 years ago

Read 2 more answers

The total stopping distance T for a vehicle is T = 2.5x + 0.5x 2 , where T is in feet and x is the speed in miles per hour. Appr

Kobotan [32]

Answer:

% change in stopping distance = 7.34 %

Step-by-step explanation:

The stooping distance is given by

$T = 2.5 x + 0.5 x^{2}$

We will approximate this distance using the relation

$f (x + dx) = f (x)+ f' (x)dx$

dx = 26 - 25 = 1

T' = 2.5 + x

Therefore

$f(x)+f'(x)dx = 2.5x+ 0.5x^{2} + 2.5 +x$

This is the stopping distance at x = 25

Put x = 25 in above equation

2.5 × (25) + 0.5× $25^{2}$ + 2.5 + 25 = 402.5 ft

Stopping distance at x = 25

T(25) = 2.5 × (25) + 0.5 × $25^{2}$

T(25) = 375 ft

Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft

% change in stopping distance = $\frac{27.5}{375}$ × 100

% change in stopping distance = 7.34 %

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3 years ago

A green number cube and a red number cube are rolled. An outcome is the pair of numbers rolled on the two different cubes. Which

Ber [7]

Answer:

None of the above

Step-by-step explanation:

The common ratio 10 means we are starting with 4.5 and multiplying that by 10 each time:

4.5*10=45

45*10=450

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As you can see, this does not match any of the answers

Read more on Brainly.com - brainly.com/question/14993026#readmore

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3 years ago