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Vadim26 [7]
3 years ago
15

Find the missing value 1/2 equals 28 over X ​

Mathematics
1 answer:
muminat3 years ago
8 0

Answer:

x = 56

Step-by-step explanation:

cross multiply. 28 times 2 and 1 times x. set them equal to each other and solve for x to get 56.

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Which number(s) below belong to the solution set of the equation? Check all
Brilliant_brown [7]

Answer:

<h2>only x = 39</h2>

Step-by-step explanation:

x + 6 = 45           <em>subtract 6 from both sides</em>

x + 6 - 6 = 45 - 6

x = 39

6 0
3 years ago
Anne owns a used car lot and in order to get cars to sell, she buys used cars at an
azamat

Answer:

It would be 2,000x+200

Step-by-step explanation:

okay it costs $200 to attend so that's a cost you are going to have to pay regardless. The $2,000 depends on how many cars you buy. So it would be 2,000 (times how ever many cars you buy) plus the $200.

3 0
3 years ago
A, B, and C are collinear, and B is between A and C. The ratio of AB to BC is 3 : 1.
S_A_V [24]

Coordinates of point C: (1,-1)

Step-by-step explanation:

In this problem, A, B and C are collinear, and B is between A and C.

The ratio AB : BC is 3 : 1.

This means that we can write the following two equations:

x_B-x_A = 3(x_C-x_B)\\y_B-y_A=3(y_X-y_B)

where:

(x_A,y_A)=(-7,3) are the coordinates of point A

(x_B,y_B)=(-1,0) are the coordinates of point B

(x_C,y_C) are the coordinates of point C

Solving the equation for x_C,

x_C = x_B + \frac{x_B-x_A}{3}=-1+\frac{-1-(-7)}{3}=1

Solving the equation for y_C,

y_C=y_B + \frac{y_B-y_A}{3}=0+\frac{0-3}{3}=-1

So, the coordinates of point C are

C(-1,1)

Learn more about how to divide segments:

brainly.com/question/3269852

brainly.com/question/11280112

#LearnwithBrainly

4 0
3 years ago
Find, correct to the nearest degree, the three angles of the triangle with the given vertices. A(1, 0, −1), B(4, −3, 0), C(1
zavuch27 [327]

Answer:

Angle at vertex  A : 59.2° B: 61.7° C : 59.1°

Step-by-step explanation:

1. First find the length of the vectors  

AB = B-A = (4-1, 3-0, 0-1) = (3, 3, -1)

AC = C-A = (1-1, 4-0, 3-1) = (0, 4, 2)

BC = C-B = (1-4, 4-3, 3-0) = (-3, 1, 3)

2. Find magnitude of the vectors

|AB| = √(3^2+3^2+〖(-1)〗^2 )=√19  

|AC| = √(0^2+4^2+2^2 )=2√5

|BC| = √(〖(-3)〗^2+1^2+3^2 )=√19

3. Find the angles between them

cos θ = (a.b)/(|a||b|) -----> θ = arc cos ((a.b)/(|a||b|))

AB, AC : θ =arc cos (AB.AC)/(|AB||AC|) = arc cos ( (3.0+3.4+ -1.2)/(√19  x 2√5)=  10/(2√95) ) =59.136, which is approximately 59.14°

AB, BC : θ =arc cos (AB.BC)/(|AB||BC|) = arc cos( (3.-3+3.1+ -1.3)/(√19  x √19)=  (-9)/19 ) = 118.27°

Because of the direction of BC is pointing relative to AB this is the angle outside the triangle, and we should find the supplementary angle.

180-118.27 = 61.73°

If we used –(BC) = CB in the formula (just negate the numerator) we would have gotten the correct angle on first try.

The 3rd angle should be what’s left after subtracting from 180°;

180-61.73-59.14 = 59.13 °

You can confirm using the formula again :

AC, BC : θ =arc cos (AC.BC)/(|AC||BC|) = arc cos( (0.-3+4.1+ 2.3)/(√19  x 2√5)=  10/(2√95) = 59.13°

Rounding everything up so they add up to 180 degrees we have Angle at vertex  A : 59.2° B: 61.7° C : 59.1°

7 0
3 years ago
A number x plus 10 is more than 2
makvit [3.9K]
X+10>2. The simplified answer is x>-8
4 0
3 years ago
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