![\bf tan(x^o)=1.11\impliedby \textit{taking }tan^{-1}\textit{ to both sides} \\\\\\ tan^{-1}[tan(x^o)]=tan^{-1}(1.11)\implies \measuredangle x=tan^{-1}(1.11)](https://tex.z-dn.net/?f=%5Cbf%20tan%28x%5Eo%29%3D1.11%5Cimpliedby%20%5Ctextit%7Btaking%20%7Dtan%5E%7B-1%7D%5Ctextit%7B%20to%20both%20sides%7D%0A%5C%5C%5C%5C%5C%5C%0Atan%5E%7B-1%7D%5Btan%28x%5Eo%29%5D%3Dtan%5E%7B-1%7D%281.11%29%5Cimplies%20%5Cmeasuredangle%20x%3Dtan%5E%7B-1%7D%281.11%29)
plug that in your calculator, make sure the calculator is in Degree mode
So they're finally here, performing for you
If you know the words, you can join in too
Put your hands together, if you want to clap
As we take you through this monkey rap!
Huh!
DK
Donkey Kong!
He's the leader of the bunch, you know him well
He's finally back to kick some tail
His coconut gun can fire in spurts
If he shoots ya, it's gonna hurt!
He's bigger, faster, and stronger too
He's the first member of the DK crew!
Huh!
DK
Donkey Kong!
DK
Donkey Kong is here
Answer:
The statement that cushion A is twice as popular as cushion B cannot be verified
Step-by-step explanation:
From the question we are told that:
Sample size n=38
Type a size A 
Type a size B
Generally the probability of choosing cushion A P(a) is mathematically given by


Generally the equation for A to be twice as popular as B is mathematically given by

Therefore Hypothesis

Generally the equation normal approx of p value is mathematically given by



Therefore from distribution table


Therefore there is no sufficient evidence to disagree with the Null hypothesis 
Therefore the statement that cushion A is twice as popular as cushion B cannot be verified
Well, you would need to compensate for the cost of the banquet hall adding an addition $700 to the goal of $1000.
If you need to raise at least $1700 you can write this inequality.
Let x represent the number of tickets sold.
15x≥1700
x≥ 114 (rounded to the nearest whole number because you can't sell half a ticket)
So, at least 114 tickets need to be sold.
Circumference: 21.991 feet
Area: 38.485 feet