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3 years ago

The sum of two numbers is 210. Determine the maximum product of these two numbers

1 answer:

6 0

If we take the two numbers 105 and 105,
if we add both these numbers we get the sum of 210
105+105 = 210
and we multiply both these numbers we get the product of 11,025.
105 x 105 = 11,025
and if we take two number 104 and 106, we get the sum of 210 but if we multiply these two numbers we get the product of 11,024 that is less than 11,025.
So the maximum product of these two numbers is 11,025.

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The sum of two numbers is 82. The larger number is eight less then five times the smaller number. What are the numbers?

bonufazy [111]

Answer:

The smaller Number = 15

The larger number = 67

Step-by-step explanation:

Let

The smaller number = x

The larger number = 5x - 8

The sum = 82

(5x - 8) + x = 82

5x - 8 + x = 82

6x - 8 = 82

Add eight to both sides

6x - 8 + 8 = 82 + 8

6x = 90

Divide both sides by 6

x = 90/6

= 15

Therefore,

The smaller number = x = 15

The larger number = 5x - 8

= 5(15) - 8

= 75 - 8

= 67

6 0

3 years ago

Help please!!!!!!!!!!!!!!!

drek231 [11]

The original side length was 12m therefore the perimeter was 36m. 12/4 is 3 so the perimeter is now 9, and the difference between them is 27.

4 0

3 years ago

Explain how to find 27% of 16 using multiplication by

just olya [345]

Answer:

4.32

Step-by-step explanation:

You can multiply 16 by 0.27 to get the answer.

16*0.27=4.32

You can check your work with estimation because 27% is about 1/4 of the number, and just by looking at the number, 4 is 1/4 of the number.

6 0

2 years ago

Read 2 more answers

In the figure below, two secants are drawn to a circle from exterior point U. Suppose that UW=45, UZ=30, and UX=22.5. Find UY

Alex777 [14]

UY = 25

hope this answer helps you dear....take care!

if u have any doubt so feel free to ask!

3 0

2 years ago

Members of the millennial generation are continuing to be dependent on their parents (either living with or otherwise receiving

Morgarella [4.7K]

Answer:

$\bf H_0:$ The mean of adults aged 18 to 32 that continue to be dependent on their parents is 0.3

$\bf H_a:$ The mean of adults aged 18 to 32 that continue to be dependent on their parents is greater than 0.3

b) 34%

c) practically 0

d) Reject the null hypothesis.

Step-by-step explanation:

Since an individual aged 18 to 32 either continues to be dependent on their parents or not, this situation follows a Binomial Distribution and, according to the previous research, the probability p of “success” (depend on their parents) is 0.3 (30%) and the probability of failure q = 0.7

According to the sample, p seems to be 0.34 and q=0.66

To see if we can approximate this distribution with a Normal one, we must check that is not too skewed; this can be done by checking that np ≥ 5 and nq ≥ 5, where n is the sample size (400), which is evident.

We can then, approximate our Binomial with a Normal with mean

$\bf np = 400*0.34 = 136$

and standard deviation

$\bf \sqrt{npq}=\sqrt{400*0.34*0.66}=9.4742$

Since in the current research 136 out of 400 individuals (34%) showed to be continuing dependent on their parents:

$\bf H_0:$ The mean of adults aged 18 to 32 that continue to be dependent on their parents is 0.3

$\bf H_a:$ The mean of adults aged 18 to 32 that continue to be dependent on their parents is greater than 0.3

So, this is a right-tailed hypothesis testing.

According to the sample the proportion of "millennials" that are continuing to be dependent on their parents is 0.34 or 34%

Our level of significance is 0.05, so we are looking for a value $\bf Z^*$ such that the area under the Normal curve to the right of $\bf Z^*$ is ≤ 0.05

This value can be found by using a table or the computer and is $\bf Z^*$ = 1.645

Applying the continuity correction factor (this should be done because we are approximating a discrete distribution (Binomial) with a continuous one (Normal)), we simply add 0.5 to this value and

$\bf Z^*$ corrected is 2.145

Now we compute the z-score corresponding to the sample

$\bf z=\frac{\bar x -\mu}{s/\sqrt{n}}$