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Masja [62]
4 years ago
9

If vector u = (5, 3) and vector v = (-1, 4), what is the component form of vector u + v?

Mathematics
1 answer:
Mrac [35]4 years ago
6 0
I think this is the answer
\binom{5}{3}  +  \binom{ - 1}{4}  =   \binom{ 4}{7}
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The cost of renting a community center is $100, with an additional cost of $10 per guest.
Marysya12 [62]

D

Step-by-step explanation:

The number of guests is the independent variable and should be between 1 and 50.  We can use a scale of 10's

The cost is the dependent variable and the minimum cost is 100 and should rise from there

The scale would be from 100 's

4 0
4 years ago
Read 2 more answers
Through (5,4) slope= - 7/5
Makovka662 [10]

For this case we have that by definition, the equation of a line of the point-slope form is given by:

y-y_ {0} = m (x-x_ {0})

Where:

m: It is the slope of the line

(x_ {0}, y_ {0}): It is a point that belongs to the line

According to the data of the statement we have to:

m = - \frac {7} {5}\\(x_ {0}, y_ {0}) :( 5,4)

Substituting in the equation we have:

y-4 = - \frac {7} {5} (x-5)

Answer:

y-4 = - \frac {7} {5} (x-5)

4 0
4 years ago
Please answer this question only if you know it! 25 points and brainliest!
krok68 [10]

Answer:

\boxed{70^\circ}

Step-by-step explanation:

Step 1. Calculate θ

\begin{array}{rcll}70^{\circ} + \theta + 60^{\circ} & = & 180^{\circ} & \text{Angles of straight line}\\130^{^{\circ}} + \theta & = & 180^{\circ}} & \\\theta & = & 50^{\circ} & \\\end{array}

Step 2. Calculate x

\begin{array}{rcll}60^{\circ} + \theta + x & = & 180^{\circ} & \text{Interior angles of triangle}\\60^{\circ} + 50^{\circ} + x & = & 180^{\circ} &\\110^{^{\circ}} + x& = & 180^{\circ} & \\\\x & = & \boxed{70^\circ} & \\\end{array}

4 0
3 years ago
PLEASE HELP ASAP Please?
Alexeev081 [22]

Answer:

c

Step-by-step explanation:

First, from A to B, x=6, but y ranges from 8 to -8. From B to C, y=-8, but x ranges from 6 to -6. From C to D, x=-6, but y ranges from -8 to 8. From D to A, y=8, but x ranges from -6 to 6.

The ranges are as follows:

- x goes from -6 to 6

- y goes from -8 to 8

There are no x values less than -6, no x values greater than 6, no y values less than -8, and no y values greater than 8. x is always greater than or equal to -6 and less than or equal to 6. y is always greater than or equal to -8 and less than or equal to 8. We can write these as inequalities as follows:

x ≥ -6

x ≤ 6

y ≥ -8

y ≤ 8

The answer that is not in these 4 is c. y ≤ -8. y is never less than -8, so this is wrong

8 0
3 years ago
HELP PLEASE<br><br> ((ATTACHMENT TO HELP ANSWER, BECAUSE THERE'S REALLY NO QUESTION WITH IT))
BabaBlast [244]
Linear- blue graph, table 2, 2x-3y=7, y=3\x +2, y=-4
Nonlinear- y= 2x^2+ 4
7 0
4 years ago
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