Because when we draw a point ,we draw a very very small line....one can see how this might lead to a problem.consider a line that is 1 inch long,what we want to looked at 1/1000 through that line it would still be a line.but,if we drew it ,it would look like a point....
Answer:
Yes . You are correct.
Step-by-step explanation:
(x + 5)^2 + (y + 10)^2 = 81.
<h3>
Answer: Choice D) </h3>
Work Shown:

We must require that
and
to avoid having 0 in the denominator. This is why choice D is the answer.
Answer:
answer to the question is A