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Lena [83]
3 years ago
6

Will mark branlist for the first one to help

Mathematics
1 answer:
Nikitich [7]3 years ago
8 0

Answer:

17°

Step-by-step explanation:

73°= EGB

EGB+ x° = 90°

so x° = 90°-73° =17°

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marusya05 [52]

Answer:

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2 years ago
Consider a sphere of radius R &gt; 0. Take two antipodal points A and B on the sphere, and another point C on the sphere. Check
aleksklad [387]

Answer:

To this question; we want to show that if two antipodal points on a sphere were A and B, for any random point C on the sphere, AC is perpendicular to BC?

Step-by-step explanation:

I would proceed by imagining the sphere in a three dimensional Cartesian coordinate system. For example, use a sphere of diameter 2 and let it sit at the origin. Then (0, 0, 1) and (0, 0, -1) are the vector locations of the “north and south poles” of the sphere.

Now choose the vector location of any point on the surface of the sphere. It will have a vector location - we’ll call it (x, y, z). Now the vectors from your point to the two poles are (-x, -y, 1-z) and (-x, -y, -1-z).

Now just form the dot product of those two vectors:

(-x, -y, 1-z) . (-x, -y, -1-z) = x^2 +y^2 + (1-z)*(-1-z)

Now the truth of your claim will be embodied in that dot product being zero:

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But that last line is just the definition of points on the surface of a sphere of radius 1, so the claim is proven.

Since R>0 and AC is perpendicular to BC, the <ACB is at right angle.

Please, find attached a simple image to show antipodal points (Two points that makes a diameter) and a point C on the sphere.

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It would be: (2/9)² = 4/81

In short, Your Answer would be Option A

Hope this helps!
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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