Solve: negative 1 over 2 x + 2 = −x + 7 (5 points)

Mathematics

1 answer:

anzhelika [568]3 years ago

6 0

Answer:

x = 10

Step-by-step explanation:

$-\dfrac{1}{2}x+2=-x+7\qquad\text{Given}\\\\\dfrac{1}{2}x=5\qquad\text{add x-2}\\\\x=10\qquad\text{multiply by 2}$

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2 1.3.1 Study: Multiplying Binomials Drag the tiles to the blanks. Distribute. - 4(x - 2) =

ehidna [41]

Answer:

I am not entirely sure what you are asking here but if I am right then the answer is -4(x-2) = 8 - 4x

Step-by-step explanation:

Multiplying binomials all you have to do is distribute the 4

Multiply -4 by x to get: -4x

Muliply -4 by -2 to get: 8 (Because two negatives make a positive)

Now you have -4x + 8

Rewrite so it flows better and the answer is:

8 - 4x

6 0

3 years ago

If 3x^2 + y^2 = 7 then evaluate d^2y/dx^2 when x = 1 and y = 2. Round your answer to 2 decimal places. Use the hyphen symbol, -,

S_A_V [24]

Taking $y=y(x)$ and differentiating both sides with respect to $x$ yields

$\dfrac{\mathrm d}{\mathrm dx}\bigg[3x^2+y^2\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[7\bigg]\implies 6x+2y\dfrac{\mathrm dy}{\mathrm dx}=0$

Solving for the first derivative, we have

$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x}y$

Differentiating again gives

$\dfrac{\mathrm d}{\mathrm dx}\bigg[6x+2y\dfrac{\mathrm dy}{\mathrm dx}\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[0\bigg]\implies 6+2\left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2+2y\dfrac{\mathrm d^2y}{\mathrm dx^2}=0$

Solving for the second derivative, we have

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=-\dfrac{3+\left(\frac{\mathrm dy}{\mathrm dx}\right)^2}y=-\dfrac{3+\frac{9x^2}{y^2}}y=-\dfrac{3y^2+9x^2}{y^3}$

Now, when $x=1$ and $y=2$ , we have

$\dfrac{\mathrm d^2y}{\mathrm dx^2}\bigg|_{x=1,y=2}=-\dfrac{3\cdot2^2+9\cdot1^2}{2^3}=\dfrac{21}8\approx2.63$

3 0

3 years ago

Find the time, amount = Rs 1375, principal =Rs 1250, Rate - 4%

TiliK225 [7]

Answer:

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