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stiks02 [169]
4 years ago
10

HELP PLEASE 100 POINTS & BRAINLIEST

Biology
1 answer:
Scilla [17]4 years ago
8 0

Answer:

For Q1, the answer is mutualism. The answer for the second question is parasitism. For the third question, the answer is commensalism. For Q4, the answer is symbiosis.

The answer for the next question is succession. For Q6 the answer is pioneer species. For Q7, the answer is secondary succession. For Q8, the answer is primary succession.

Explanation:

  1. <u>Mutualism</u>: It is a type of ecological interaction in which two similar or different species occupy the same habitat. Both benefit from this kind of association. E.g The <em>Oxpecker</em> bird lives on zebra. It eats all the parasites on top of zebra.
  2. <u>Parasitism</u>: In this type of interaction, one organism benefits while the other gets damaged. E.g <em>Tick </em>which feeds on human blood.
  3. <u>Commensalism</u>: In this case, one organism enjoys the benefits while the other neither gets the benefits nor gets harmed.
  4. <u>Symbiosis</u>: In this relationship, both organisms live happily by mutually benefiting from each other. E.g A <em>fungus and a plant</em> live together in <u>mycorrhizae.</u>
  5. <u>Succession</u>: It is a gradual change in the structure of species in an ecological community.
  6. <u>Pioneer species</u>: These species are the first one to inhabit barren wastelands. E.g <em>lichen</em> are seen on rocks.
  7. <u>Secondary succession</u>: It is type of succession in which plants and other animals rehabilitate an area destroyed by floods and fire. In this kind of succession, soil is already present.
  8. <u>Primary succession</u>: In this, the organisms try to inhabit a lifeless place with no top soil and vegetation.

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independent assortment

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Answer:

The maximum no. of RFUs collected in the purification procedure = 3.05 \times 10^5 RFUs

Explanation:

No. of RFUs in a 200 ul (0.2ml) aliquot = 5000 RFUs

So, No. of RFUs in G3-500 ml culture = 5000 \times \frac{500 ml}{0.2 ml} RFUs

                                                               = 5000 \times 2500 RFUs  

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Similarly, No. of RFUs in a G3-15ml sample = 5000 \times \frac{15 ml}{0.2 ml} RFUs

                                                                          = 5000 \times 75 RFUs

                                                                          = 3.75 \times 10^5 RFUs

The maximum no. of RFUs collected in the purification procedure

= 3.75 \times 10^5 \times 80% RFUs

= 3.75 \times 10^5 \times 0.80 RFUs

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z    Zz        zo

z    Zz        zo

The males will have two copies of the alleles of the genes present on the Z chromosomes. As females have only one Z chromosome, they will have only one allele for the genes present on the Z chromosome.

The results from the punnet square show that there will be chance that the females of the F2 progeny will have curved-beaks.

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