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Delicious77 [7]
3 years ago
12

The highlighted regions are bases. What is the lateral surface area of

Mathematics
1 answer:
Natali5045456 [20]3 years ago
6 0

Answer:

Option "C" is the correct answer to the following question.

The lateral surface area of  cube = 144  Ft²

Step-by-step explanation:

Given:

Side of cube = 6 Ft

Find:

The lateral surface area of  cube =?

Computation:

⇒ The lateral surface area of  cube = 4a²

⇒ The lateral surface area of  cube = 4 × 6 × 6

⇒ The lateral surface area of  cube = 144  Ft²

All sides of the cubes are equal. The lateral surface area of  cube is also known as the curved surface area of the cube.

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RECURSIVE: f(n)=f(n-1)+4

EXPLICIT: f(n)=3+4n

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Two ships leave a harbor together, traveling on courses that have an angle of 135°40' between them. If they each travel 402 mile
mario62 [17]

Answer:

Therefore they are 734.106 miles apart.

Step-by-step explanation:

Given that ,

Two ships have a harbor together. The angle between two ships  is  135°40'. Each of two ships travel 402 miles.

It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.

Let ∠B= 135°40', and AB = 402 miles , BC =  402 miles

Then the distance between the ships = AC

We know

The sum of all angles = 180°

⇒∠A+∠B+∠C=180°

⇒∠A+135°40'+∠C=180°

⇒2∠A= 180°- 135°40'      [ since ∠A=∠C]

⇒2∠A=44°60'

⇒∠A= 22°30'

Again we know that,

\frac{AB}{sin\angle C}=\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Taking last two ratio,

\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Putting the value of BC , AC ,∠A,∠B

\frac{402}{sin 22^\circ30'}=\frac{AC}{sin 135^\circ40'}

\Rightarrow AC=\frac{402 \times sin135^\circ40'}{sin 22^\circ30'}

         ≈734.106 miles

Therefore they are 734.106 miles apart.

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3 years ago
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Answer:

\sqrt{11}

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