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2 years ago

Subtract and simplify. (2y + 14.6m + 3.8) – (34.8m + 15.6 + 2y)

Mathematics

2 answers:

irina1246 [14]2 years ago

5 0

Answer:

-20,2m-11,8

Step-by-step explanation:

rewrite it

2y+14,6m+3,8-(34,8m+15,6-2y)

remove the opposites

and then simplify

-20,2m-11,8

im not sure if this makes sense

dem82 [27]2 years ago

4 0

Answer is : -20.2m-11.8

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What is the solution to the inequality -4 x < 8?

alekssr [168]

Answer:

The solution of the inequality is x < -2.

Step-by-step explanation:

Let's simplify the inequality first.

=> -4x < 8
=> -4x/4 < 8/4
=> -x < 2
=> x < -2

Hence, the solution of the inequality is x < -2.

Hoped this helped.

$BrainiacUser1357$

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2 years ago

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alexandr402 [8]

Answer:

option 3

Step-by-step explanation:

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2 years ago

What is midpoint of A(2, 3) and B(-2, 5)?

Elis [28]

Answer:

The midpoint of A and B is (0, 4).

Step-by-step explanation:

Use the midpoint formula, ((x₁ + x₂)/2 , (y₁ + y₂)/2)

First, solve for the x part.

(2 + (-2))/2

0/2

So the x-coordinate of the midpoint is 0.

Then, solve for the y part.

(3 + 5)/2

8/2

So the y-coordinate of the midpoint is 4.

7 0

3 years ago

Find maclaurin series

Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

$\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}$

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

$\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}$

The first 3 terms of the series are

$\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}$

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

$\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}$

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

$\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}$

7 0

2 years ago

Mrs lane took a survey of the types of pants her students were wearing. She collected the data of the types of pants her student

kirill [66]

It is always important to go through the given problem first to get a concept of the requiremement. Then all the information's available from the question has to be noted down in such a manner that there would be no need to look at the question while solving.
Total number of students wearing jeans = 10
Total number of students wearing shorts = 9
Total number of students wearing capris = 2
Then the total number of students surveyed by Mrs Lane = (10 + 9 + 2)
= 21
Now percentage of students wearing shorts = (9/21) * 100
   = (3/7) * 100
   = 300/7
   = 42.85 percent
So a total percentage of 42.85% of the students were wearing shorts.

5 0

3 years ago