'll use the binomial approach. We need to calculate the probabilities that 9, 10 or 11
<span>people have brown eyes. The probability that any one person has brown eyes is 0.8, </span>
<span>so the probability that they don't is 1 - 0.8 = 0.2. So the appropriate binomial terms are </span>
<span>(11 C 9)(0.8)^9*(0.2)^2 + (11 C 10)(0.8)^10*(0.2)^1 + (11 C 11)(0.8)^11*(0.2)^0 = </span>
<span>0.2953 + 0.2362 + 0.0859 = 0.6174, or about 61.7 %. Since this is over 50%, it </span>
<span>is more likely than not that 9 of 11 randomly chosen people have brown eyes, at </span>
<span>least in this region. </span>
<span>Note that (n C r) = n!/((n-r)!*r!). So (11 C 9) = 55, (11 C 10) = 11 and (11 C 0) = 1.</span>
Step-by-step explanation:
step 1. The x values refer to the domain of the function.
step 2. if you set y = 0 and solve the quadratic equation the x values refer to the point the graph crosses the x axis.
Answer:
744
Step-by-step explanation:
12a^2 + 4b
Plug-in:
12(8)^2 + 4(-6)
12(64) + 4(-6)
768 - 24
744
If a bag of pumpkin seeds must weigh within 2.1 grams in order to be accepted, each bags must weigh between (400-2.1) grams and (400+2.1) grams. This means that if a bag weighs less than 397.9 grams (x<397.9) or more than 402.1 grams (x>402.1) it will be rejected. Therefore, 397.9>x>402.1 is the range of rejected bags.
