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gogolik [260]
3 years ago
11

Can someone please help me with this?

Mathematics
1 answer:
Pavel [41]3 years ago
4 0

Step-by-step explanation:

1 year = 12 months

2yrs = 24 months

F(c) =100+5(24)

= 100+120

= $220

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How do you identify a rational equation?
soldier1979 [14.2K]

Answer:

\frac{P(X)}{Q(X)}

Step-by-step explanation:

it is an equation containing at least one fraction whose numerator, denominator are polynomials.

6 0
2 years ago
Explains how to find n, the number of copies the machine can make in one minute and How long will it take the machine to print 5
Rudik [331]

Answer:

n = 65m

Number of minutes is 80 minutes

Step-by-step explanation:

Given

The attached table

Calculating the number of copies the machine can make in a minute

Represent number of minutes with m and number of copies with n

First, we need to calculate the ratio of m to n

<em></em>Ratio = \frac{n}{m}<em></em>

<em>When m = 5; n = 325</em>

Ratio = \frac{325}{5}

Ratio = 65

<em>When m = 10; n = 650</em>

Ratio = \frac{650}{10}

Ratio = 65

<em>When m = 15; n = 975</em>

Ratio = \frac{975}{15}

Ratio = 65

When we continue for other values of m and n, the ratio remains the same;

So; we make use of Ratio = \frac{n}{m} to determine the relationship between m and n

Substitute 65 for Ratio

65 = \frac{n}{m}

Multiply both sides by m

m * 65 = \frac{n}{m} * m

65m = n

n = 65m

This implies that, you have to multiply the number of minutes by 65 to get the number of copies

Calculating the number of minutes to print 5200 copies;

In this case;

Ratio = 65 and n = 5200

So;

Ratio = \frac{n}{m} becomes

65 = \frac{5200}{m}

Multiply both sides by m

65 * m = \frac{5200}{m} * m

65 * m = 5200

Divide both sides by 65

\frac{65 * m}{65} = \frac{5200}{65}

m = \frac{5200}{65}

m = 80

<em>Hence; number of minutes is 80 minutes</em>

8 0
3 years ago
If A, B, and C are integers between 1 and 10 (inclusive), how many different combinations of A, B, and C exist such that A
Marianna [84]

\fontsize{18}{10}{\textup{\textbf{The number of different combinations is 120.}}}

Step-by-step explanation:

A, B and C are integers between 1 and 10  such that A<B<C.

The value of A can be minimum 1 and maximum 8.

If A = 1, B = 2, then C can be one of 3, 4, 5, 6, 7, 8, 9, 10 (8 options).

If A = 1, B = 3, then C has 7 options (4, 5, 6, 7, 8, 9, 10).

If A = 1, B = 4, then C has 6 options (5, 6, 7, 8, 9, 10).

If A = 1, B = 5, then C has 5 options (6, 7, 8, 10).

If A = 1, B = 6, then C has 4 options (7, 8, 9, 10).

If A = 1, B = 7, then C has 3 options (8, 9, 10).

If A = 1, B = 8, then C has 2 options (9, 10).

If A = 1, B = 9, then C has 1 option (10).

So, if A = 1, then the number of combinations is

n_1=1+2+3+4+5+6+7+8=\dfrac{8(8+1)}{2}=36.

Similarly, if A = 2, then the number of combinations is

n_2=1+2+3+4+5+6+7=\dfrac{7(7+1)}{2}=28.

If A = 3, then the number of combinations is

n_3=1+2+3+4+5+6=\dfrac{6(6+1)}{2}=21.

If A = 4, then the number of combinations is

n_4=1+2+3+4+5=\dfrac{5(5+1)}{2}=15.

If A = 5, then the number of combinations is

n_5=1+2+3+4=\dfrac{4(4+1)}{2}=10.

If A = 6, then the number of combinations is

n_6=1+2+3=\dfrac{3(3+1)}{2}=6.

If A = 7, then the number of combinations is

n_7=1+2=\dfrac{2(2+1)}{2}=3.

If A = 3, then the number of combinations is

n_8=1.

Therefore, the total number of combinations is

n\\\\=n_1+n_2+n_3+n_4+n_5+n_6+n_7+n_8\\\\=36+28+21+15+10+6+3+1\\\\=120.

Thus, the required number of different combinations is 120.

Learn more#

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What is 43.78 in word form?​
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forty-three and seventy-eight hundredths

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