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Afina-wow [57]
3 years ago
8

A jet ski depreciates at 11% of its original value each year. If the jet ski was $8,000 at its time of purchase, what is the val

ue of the jet ski after 5 years? (1 point)
Mathematics
2 answers:
dsp733 years ago
4 0
Compounded depreciation formula:

A = P(1 - r)ⁿ , where P = original price, r= rate of depreciation, n = number of years and A = actual value (after depreciation):

A= $8000(1 - 11%)⁵ = 8000(0.89)⁵ = 4,467.24 ≈$4,467
Lyrx [107]3 years ago
4 0
Answer:

$4,467.25

Solving:

If the jet ski depreciates at 11% of its original value each year, each year the new value will be 89% of the value the previous year.

x = the value of the jet ski

t = the number of years

x = 8000 ( 0.89 )^t

8000 ( 0.89 )^5 = <span>4467.2475592 = $4,467.25
</span>
Round your answer once calculated.


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The 18th term of an arithmetic sequence is 49 and the first term is 15.
Tju [1.3M]

Answer:

33

Step-by-step explanation:

49-15=34

34/17=2

For this sequence, you can write this function:

f(x)=15+2(x-1)

Check:

f(18)=15+2(18-1)

f(18)=15+2(17)

f(18)=15+34

f(18)=49

So:

f(10)=15+2(10-1)

f(10)=15+2(9)

f(10)=15+18

f(10)=33

5 0
3 years ago
HELP PLEASE PLEASE I WILL GIVE BRAINLIEST
podryga [215]

In the top the "f(x)" equals 9, now they are asking you to add onto the 9 by 1 causing it to be 10. If you did the first few you would have noticed that it takes 9 in order to get to 5 from -4.

here are the answers btw:

8 0
3 years ago
9x-2y=11 <br> 5x-2y=15 <br> what is the solution to the above system of equations<br> ASAP
natali 33 [55]

9x - 2y = 11 ... (i)

5x - 2y = 15 ... (ii)

Subtracting equation (ii) from (i) we get;

4x + 0 = -4

4x=-4 , x = -1

Replacing x = -1 in equation (i) we get;

9(-1) - 2y = 11

-9 - 2y = 11

-2y = 20

y = 20 ÷ -2 = -10

The solution to the system of equations is (-1,-10).

8 0
3 years ago
Read 2 more answers
Question from ucscout need help asap
Kobotan [32]

Answer:

A.S.A congurency.

please mark me brainliest and follow me my friend.

5 0
2 years ago
HELP!!!!!
podryga [215]
Solve for the x-max or h :\
-b/(2a)=-8/(2*-2)=2=k
plug it in to equation to get k:/
y(2)=-2(2)^2+8(2)+3
-8+16+3=11=k
y=a(x-2)^2+11&#10;
solve for a by pluging (0,0)
then a= -11/4
y=-11/4(x-2)^2+11

8 0
3 years ago
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