Ask question

Ask question

All categories

goldfiish [28.3K]

4 years ago

8

If a movie ticket costs $0.69 in 1960, $1.55 in 1970, $2.60 in 1980, $4.23 in 1990 and $5.39 in 2000, what is the average rate o

f change from 1960 to 2000.

1 answer:

harina [27]4 years ago

4 0

The average rate of change from 1960 to 2000 was $2.90

You might be interested in

Tryrone purchased a container of juice that contains 150 calories. the label says that 70% of the calories are from carbohydrate

serious [3.7K]

The answer is 45 calories

3 0

3 years ago

A right triangle has base x meters and height h meters, where h is constant and x changes with respect to time t, measured in se

aksik [14]

The relationship between dθ/dt, the rate of change of θ with respect to time, and dx/dt, the rate of change of x with respect to time is $\frac{d\theta}{dt} = \frac{h}{x\sqrt{x^2+y^2} }\frac{dx}{dt}$

Given the following parameters:

Adjacent side = x

Opposite side = h

The angle of elevation = θ

According to SOH CAH TOA identity;

$tan \theta =\frac{Opposite}{Adjacent}$

Substitute the given values into the formula

$tan \theta =\frac{h}{x}$

$\theta= tan^{-1}\frac{h}{x}$

Differentiate with respect to x

$\frac{d \theta}{dx} = \frac{h}{x\sqrt{x^2+y^2} }$

According to the chain rule,

$\frac{d\theta}{dt} =\frac{d\theta}{dx} \times \frac{dx}{dt}\\\frac{d\theta}{dt} = \frac{h}{x\sqrt{x^2+y^2} }\frac{dx}{dt}$

Hence the relationship between dθ/dt, the rate of change of θ with respect to time, and dx/dt, the rate of change of x with respect to time is $\frac{d\theta}{dt} = \frac{h}{x\sqrt{x^2+y^2} }\frac{dx}{dt}$

Learn more on the rate of change here: brainly.com/question/11883878

8 0

2 years ago

Consider the series 3 + 5 + 7 + 9 + ... + 2n + 1. Write Sk and Sk + 1.

iVinArrow [24]

Answer:

?

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Any time a zero is in the denominator of a fraction we call that expression undefined? How would you explain why dividing by zer

lana [24]

When dividing by zero you can’t divide anything With it and it can’t equals zero because that would be wrong it would have to be undefined

5 0

3 years ago

If dy/dx=2xy and y(0)=1.<br> What is y(1) equal to?

Llana [10]

dy/dx = 2xy
dy/y = (2x)dx
INT(1/y)dy = INT(2x)dx
ln y + c = x^2 + d
ln y = x^2 + constant
y = e^(x^2 + constant)

1 = e^constant ... so constant=0 ... so y = e^(x^2)

Verification:

y = e^(x^2)
dy/dx = 2x*e^(x^2) = 2xy
<span>and e^(0^2) = e^0 = 1

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!</span>

4 0

4 years ago