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rodikova [14]
2 years ago
12

Find the new price for the markdown. Round to the nearest cent if necessary. $12.99 marked down 25%

Mathematics
1 answer:
Y_Kistochka [10]2 years ago
8 0
$9.74

I like to do these equations backwards and multiply the first number by the opposite of it. ( think 1- the percent as a decimal) however, you can do this by converting the percent into a decimal and then subtracting that from the original number.

Have a great day!
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The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9
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Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

<em>The height </em>h(t)<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>h(t) = 3 +90\cdot t -16\cdot t^{2}<em>, where </em>t<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

3+90\cdot t -16\cdot t^{2} = 84

16\cdot t^{2}-90\cdot t +81 = 0 (1)

By Quadratic Formula:

t_{1,2} = \frac{90\pm \sqrt{(-90)^{2}-4\cdot (16)\cdot (81)}}{2\cdot (16)}

t_{1} = 4.5\,s, t_{2} = 1.125\,s

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

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Step-by-step explanation:

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