What is the square root of 6

Peg rode her bike for 1 \text{ kilometer}1 kilometer1, start text, space, k, i, l, o, m, e, t, e, r, end text before stopping. L

USPshnik [31]

Answer:

2x45+67

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Step-by-step explanation:

6 0

3 years ago

#1. 8(s+3)=72

Jobisdone [24]

1. s=6
2. z=16
3. t=2
4.n=98
5.r=-1.8
6.w=74/45

Hope these are correct

6 0

3 years ago

Write the linear equation 2x + 3y = 6 in slope-intercept form. Be sure to write the slope as an improper or proper fraction.

Vera_Pavlovna [14]

Answer:

y=-2/3x+2

Step-by-step explanation:

Slope Formula: Y=mx+b

6 0

3 years ago

Last week, Pauline worked 35 hours and made $280. The boss at Pauline’s company makes $600 a week. How many hours would Pauline

notka56 [123]

Pauline needs to work for 75 hours to make $600

Given that Pauline worked 35 hours and made $280, this can be written as:

35 hours = $280

If Pauline’s company makes $600 a week, this can be expressed as:

x = $600

35/x = 280/600

35/x = 28/60

28x = 35 * 60

28x = 2100

x = 2100/28

x = 75

This means that Pauline needs to work for 75 hours to make $600

Learn more here: brainly.com/question/3796978

5 0

3 years ago

The annual rainfall in a certain region is approximately normally distributed with mean 41.4 inches and standard deviation 5.7 i

stich3 [128]

Complete question :

The annual rainfall in a certain region is approximately normally distributed with mean 41.4 inches and standard deviation 5.7 inches. Round answers to the nearest tenth of a percent. a) What percentage of years will have an annual rainfall of less than 43 inches? b) What percentage of years will have an annual rainfall of more than 39 inches? c) What percentage of years will have an annual rainfall of between 38 inches and 42 inches?

Answer:

0.61053

0.66314

0.26647

Step-by-step explanation:

Given that :

Mean (m) = 41.4 inches

Standard deviation (s) = 5.7 inches

a) What percentage of years will have an annual rainfall of less than 43 inches?

P(x < 43)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (43 - 41.4) / 5.7 = 0.2807017

p(Z < 0.2807) = 0.61053 ( Z probability calculator)

b) What percentage of years will have an annual rainfall of more than 39 inches? c)

P(x > 39)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (39 - 41.4) / 5.7 = −0.421052

p(Z > −0.421052) = 0.66314 ( Z probability calculator)

What percentage of years will have an annual rainfall of between 38 inches and 42 inches?

P(x < 38)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (38 - 41.4) / 5.7 = −0.596491

p(Z < −0.596491) = 0.27545 ( Z probability calculator)

P(x < 42)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (42 - 41.4) / 5.7 = 0.1052631

p(Z < 0.1052631) = 0.54192 ( Z probability calculator)

0.54192 - 0.27545 = 0.26647

6 0

3 years ago