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cluponka [151]
3 years ago
7

Last week, Pauline worked 35 hours and made $280. The boss at Pauline’s company makes $600 a week. How many hours would Pauline

need to work to make $600?
Mathematics
1 answer:
notka56 [123]3 years ago
5 0

Pauline needs to work for 75 hours to make $600

Given that Pauline worked 35 hours and made $280, this can be written as:

35 hours = $280

If Pauline’s company makes $600 a week, this can be expressed as:

x = $600

35/x = 280/600

35/x = 28/60

28x = 35 * 60

28x = 2100

x = 2100/28

x = 75

This means that Pauline needs to work for 75 hours to make $600

Learn more here: brainly.com/question/3796978

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hodyreva [135]
Answer:
line a and b are parallel
line c is not perpendicular because it is not 3

step-by-step explanation:
if the slope is the same it is parallel
if the slope is the complete opposite it is perpendicular
lines a and b are parallel with a slope of -1/3
(0, 5) (3, 4)
m = 4 - 5 / 3 - 0
m = -1 / 3
m = -1/3
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m = -1 / 3
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line c is perpendicular to lines a and b the slope is
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m = 5 - 0 / 2 - 0
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3 years ago
Which are partial products for 89 × 25?
Keith_Richards [23]
D is the answer. hth.
6 0
3 years ago
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A print shop borrows $6700 from a credit union for 338 days the credit union charges simple interest at an annual rate of 10% fo
bekas [8.4K]

Answer:

The total he would have to pay back would be $7,320.44

Step-by-step explanation:

(I'm assuming you want the total amount he needs to pay back)

6700 x 0.10 = 670 per year

670 ÷ 365 = 1.835616438356164

1.835616438356164 × 338 = 620.44

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Which tables represent constant functions?
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A function is a law that tells you how to associate inputs (x values) and outputs (y values).

In the case of constant functions, it doesn't matter which input you choose, the ouput must always be the same.

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Please help!
Gemiola [76]

The earning of the salesperson is an illustration of a linear function.

The possible functions in the two scenarios are: \mathbf{I(s) = 0.1s + 2500} and \mathbf{I(s) = 0.05s + 2000}\\

The function is given as:

\mathbf{I(s) = 0.1s + 2000}

When the base salary is increased, a possible function is:

\mathbf{I(s) = 0.1s + 2500}

This is so, because 2500 is greater than 2000

When the commission rate is decreased, a possible function is:

\mathbf{I(s) = 0.05s + 2000}\\

This is so, because 0.05 is less than 0.1

So, the possible functions in the two scenarios are:

\mathbf{I(s) = 0.1s + 2500} and \mathbf{I(s) = 0.05s + 2000}\\

See attachment for the graphs of both functions

Read more about linear equations at:

brainly.com/question/21981879

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