Answer:
268,435,456
Step-by-step explanation:
Multiply by -4
![\bf 0.444444444\overline{4}\impliedby \textit{and keeps on going}\\\\ -------------------------------\\\\ \textit{let's say }\boxed{x=0.444444444\overline{4}}\quad \textit{ thus }10\cdot x=4.44444444\overline{4} \\\\\\ \textit{wait a minute! }4.44444444\overline{4}\textit{ is really just }4+0.444444444\overline{4}](https://tex.z-dn.net/?f=%5Cbf%200.444444444%5Coverline%7B4%7D%5Cimpliedby%20%5Ctextit%7Band%20keeps%20on%20going%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0A%5Ctextit%7Blet%27s%20say%20%7D%5Cboxed%7Bx%3D0.444444444%5Coverline%7B4%7D%7D%5Cquad%20%5Ctextit%7B%20thus%20%7D10%5Ccdot%20x%3D4.44444444%5Coverline%7B4%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ctextit%7Bwait%20a%20minute%21%20%7D4.44444444%5Coverline%7B4%7D%5Ctextit%7B%20is%20really%20just%20%7D4%2B0.444444444%5Coverline%7B4%7D)
![\bf \textit{but we know }x=0.444444444\overline{4} \textit{ so then }4+0.444444444\overline{4}=\boxed{4+x} \\\\\\ \textit{wait a second! }10\cdot x\implies 10x=4.444444444\overline{4}=4+x \\\\\\ thus\qquad 10x=4+x\implies 10x-x=4\implies 9x=4\implies \boxed{x=\cfrac{4}{9}}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bbut%20we%20know%20%7Dx%3D0.444444444%5Coverline%7B4%7D%20%5Ctextit%7B%20so%20then%20%7D4%2B0.444444444%5Coverline%7B4%7D%3D%5Cboxed%7B4%2Bx%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ctextit%7Bwait%20a%20second%21%20%7D10%5Ccdot%20x%5Cimplies%2010x%3D4.444444444%5Coverline%7B4%7D%3D4%2Bx%0A%5C%5C%5C%5C%5C%5C%0Athus%5Cqquad%2010x%3D4%2Bx%5Cimplies%2010x-x%3D4%5Cimplies%209x%3D4%5Cimplies%20%5Cboxed%7Bx%3D%5Ccfrac%7B4%7D%7B9%7D%7D)
you can check in your calculator.
anyhow, to get the "recurring decimal to fraction", you start by setting to some variable, "x" in this case, then move the repeating part to the left of the point by multiplying it by some power of 10, and then do the equating.
Answer:
SSS, SAS, ASA, AAS, HL
Step-by-step explanation:
1. SSS (side side side) says if 3 sides of one triangle are congruent to 3 sides of another triangle, then the 2 triangles are congruent.
2. SAS (side angle side) says if 2 sides and the included angle of a triangle are congruent to 2 sides and the included angle of another triangle, then the 2 triangles are congruent.
3. ASA (angle side angle) says if 2 angles and the included side of a triangle are congruent to 2 angles and the included side of another triangle, then the 2 triangles are congruent.
4. AAS (angle angle side) says if 2 angles and the none included side of one triangle are congruent to the corresponding parts of another triangle, then the 2 triangles are congruent.
5 HL (hypotenuse leg) says if 2 right triangles that have a congruent hypotenuse and a corresponding congruent leg, then the 2 triangles are congruent.
Because it is a rectangle, the sides are equal, and they share the same hypotenuse.
Answer:
73
Step-by-step explanation:
you write 12 instead of b