A restaurant is planning its staffing for weekday dinners. It finds that the number of customers is normally distributed. Which
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Division yields
Now for partial fractions: you're looking for constants <em>a</em>, <em>b</em>, and <em>c</em> such that
which gives <em>a</em> + <em>b</em> = 2, <em>c</em> = 0, and 2<em>a</em> = -7, so that <em>a</em> = -7/2 and <em>b</em> = 11/2. Then
Now, in the integral we get
The first two terms are trivial to integrate. For the third, substitute <em>y</em> = <em>x</em> ² + 2 and d<em>y</em> = 2<em>x</em> d<em>x</em> to get
Using concepts of <u>sample and population</u>, it is found that the sample variance is representative of 362 and 5530 customers ages, option D.
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In sampling, the <u>information is taken from a sample</u>, and is used to <u>estimate it for the whole population</u>.
- In this problem, we have a sample of 362 and a population of 5530 customers.
- The sample variance
is calculated from the sample, and used as an estimate for the population variance. Thus, it can be said that it represents both 362 and 5530 customers, and the correct option is D.
A similar problem is given at brainly.com/question/4086221