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Aleks04 [339]
3 years ago
7

H(x) = 4x-2, then which of the following is the solution to h(x)= 3

Mathematics
1 answer:
UkoKoshka [18]3 years ago
7 0

Answer:

h(x)=10

Step-by-step explanation:

h(x)= 4x-2                       h(x)=3

h(x)= 4(3)-2

h(x)= 12-2

h(x)= 10

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Which fraction is equivalent to 4 over negative 15
Artist 52 [7]

Answer:

- 4/15

Step-by-step explanation:

Just take 4 and 15 make that a fraction make the fraction a negative not the 15 because they will be the same thing no matter where you place it

7 0
4 years ago
Jack bought a mug for 10$ and then sold it and got 20% profit. how much did jack sell his mug for?
alexgriva [62]

Answer:

20% of 10 is 2    

10 + 2 = 12   ye got 2 dollars back.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
the area of a rectangle is 30 to the square root of 3750 square inches, and the length is 3 to the square root of 250 inches. wh
uranmaximum [27]
<h3><u>Answer</u><u>:</u></h3>

  • \sf { width =10 \sqrt{15} \:inches}

<h3><u>Solution</u><u>:</u></h3>

<em>We are given that:</em>

  • Area of rectangle is 30√3570
  • Length of the rectangle is 3√250

<u>Area </u><u>of </u><u>rectangle </u><u>is </u><u>given </u><u>by:</u>

\implies\quad{\pmb{ \sf{Area = length\times width}} }

<u>Hence, putting the values in the formula:</u>

\implies\quad \sf{ A = l\times w}

\implies\quad \sf{ 30\sqrt{3750}=3\sqrt{250}\times w}

\implies\quad \sf{3\sqrt{250}\times w = 30\sqrt{3750} }

\implies\quad \sf{ w =\dfrac{30\sqrt{3750}}{3\sqrt{250}}}

\implies\quad \sf{ w =10\dfrac{\sqrt{3750}}{\sqrt{250}}}

\implies\quad \sf{ w = 10\times\sqrt{\dfrac{3750}{250}}}

\implies\quad \underline{\underline{\pmb{\sf{ w =10\sqrt{15}}}}}

8 0
3 years ago
Help me below pleasse
pashok25 [27]
The answer is c (7,8)


3 0
3 years ago
Read 2 more answers
5c + 16.5 = 13.5 + 10c
Leya [2.2K]

Answer:

Hello!

________________________

5c + 16.5 = 13.5 + 10c

Exact Form:  c = 3/5

Decimal Form: c = 0.6

Step-by-step explanation: Isolate the variable by dividing each side by factors that don't contain the variable.

Hope this helped you!

8 0
3 years ago
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