Question

Find the possible value or values of n in the quadratic equation 2n2 – 7n + 6 = 0.

Answer 1

$2n^2 - 7n + 6 = 0\\ 2n^2-4n-3n+6=0\\ 2n(n-2)-3(n-2)=0\\ (2n-3)(n-2)=0\\ n=\dfrac{3}{2} \vee n=2$