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3 years ago

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Rhonda is drawing a 3-inch square inside an isosceles triangle with two side lengths measuring 7 inches and 14 inches. Which of

the following is the length of the third side of the triangle?
A) 7 in.
B) 9 in.
C) 12 in.
D) 14 in.

1 answer:

Aleksandr-060686 [28]3 years ago

5 0

Answer:

7

Step-by-step explanation:

I just need to type more or my answer gets auto delete but yeah it is 7

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What is the y-intercept of this function?<br> f(x) = 2(x - 7)2 – 32

LUCKY_DIMON [66]

We are given the following function and want to find the y-intercept:

$f(x)=2(x-7)^2-32$

Just substitute the value x=0 into the equation to find the value of the y-intercept:

$y=2(0-7)^2-32$

Simplify

$=2(49)-32$

Simplify again

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Read 2 more answers

What simple interest rate would allow $6000 to grow to an amount of $14550 in 10 years?

Harman [31]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{ \: 14.25 \: \% \: }}}}}$

Step-by-step explanation:

Given,

Principal ( P ) = $ 6000

Amount ( A ) = $ 14550

Time ( T ) = 10 years

Rate ( R ) = ?

<u>Finding </u><u>the </u><u>Interest</u>

The sum of principal and interest is called an amount.

From the definition,

$\boxed{ \sf{Amount = \: Principal + Interest}}$

plug the values

⇒ $\sf{14550 = 6000 + Interest}$

Swap the sides of the equation

⇒ $\sf{6000 + Interest = 14550}$

Move 6000 to right hand side and change its sign

⇒ $\sf{Interest = 14550 - 6000}$

Subtract 6000 from 14550

⇒ $\sf{Interest = \: 8550 \: }$

Interest = $ 8550

<u>Finding </u><u>the </u><u>rate </u>

${ \boxed{ \sf{Rate = \frac{Interest \times 100}{Principal \times Time}}}}$

plug the values

⇒ $\sf{ Rate = \frac{8550 \times 100}{6000 \times 10} }$

Calculate

⇒ $\sf{Rate = \frac{855000}{60000} }$

⇒ $\sf{Rate = 14.25 \: \% \: }$

Hope I helped!

Best regards!!

8 0

3 years ago

Apr 24,8:28:53 AM<br> Find the 98th term of the arithmetic sequence -10,-8, -6, ...

Nata [24]

Answer: 184

Step-by-step explanation:

The nth term of am arithmetic sequence is calculated as:

Nth term= a+(n-1)d

where a = first term

d = common difference

a = -10

d = -8 -(-10) = -8+10 = 2

98th term= a+(n-1)d

= -10 + (98-1)(2)

= -10 + (97×2)

= -10 + 194

= 184

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3 years ago