The problem simplified is 36√ 2abc
A unit rate is when it is in simplest form
Answer:
0.03 is the probability that for the sample mean IQ score is greater than 103.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 100
Standard Deviation, σ = 16
Sample size, n = 100
We are given that the distribution of IQ score is a bell shaped distribution that is a normal distribution.
Formula:
Standard error due to sampling =

P( mean IQ score is greater than 103)
P(x > 103)
Calculation the value from standard normal z table, we have,

0.03 is the probability that for the sample mean IQ score is greater than 103.
Answer:
see below
Step-by-step explanation:
-1/2 * (6x + 10) = 13
Distribute -1/2
–3x – 5 = 13
Add 5 to each side
-3x-5+5 = 13+5
–3x = 18
Divide each side by -3
-3x/-3 = 18/-3
x = -6