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2 years ago

(08.03)Jasper is using the following data samples to make a claim about the house values in his neighborhood:

1 answer:

7 0

I think its D (or #4 - He Should use the mean because there are no outliers that affect the mean) because the Median would be $175,000 but the Mean would be $638,400. It's honestly almost up to you.

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Arnold took a tray of cookies to a party 90% of the cookies were eating only these 5 remain

e-lub [12.9K]

Answer:

50 in total, 45 were eaten

Step-by-step explanation:

If there's only 10% left and 10% is 5 cookies, then that means for every 10% is 5 cookies so 90 x 5 = 45

8 0

2 years ago

If 12,025 was invested at 3.25% compounded monthly 3 years, how much interest will be earned

wariber [46]

Answer:

$1,229.75

Step-by-step explanation:

Lets use the compound interest formula provided to solve this:

$A=P(1+\frac{r}{n} )^{nt}$

P = initial balance

r = interest rate (decimal)

n = number of times compounded annually

t = time

First, change 3.25% into a decimal:

3.25% -> $\frac{3.25}{100}$ -> 0.0325

Since the interest is compounded monthly, we will use 12 for n. Lets plug in the values now:

$A=12,025(1+\frac{0.0325}{12})^{12(3)}$

$A=13,254.75$

Lastly, subtract A from P to get the interest earned:

$13,254.75 - 12,025 = 1,229.75$

6 0

2 years ago

Implicit differentiation Please help

Anvisha [2.4K]

Answer:

$y''(-1) =8$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Algebra I

Factoring

Calculus

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

-xy - 2y = -4

Rate of change of the tangent line at point (-1, 4)

Step 2: Differentiate Pt. 1

Find 1st Derivative

Implicit Differentiation [Product Rule/Basic Power Rule]: $-y - xy' - 2y' = 0$
[Algebra] Isolate y' terms: $-xy' - 2y' = y$
[Algebra] Factor y': $y'(-x - 2) = y$
[Algebra] Isolate y': $y' = \frac{y}{-x-2}$
[Algebra] Rewrite: $y' = \frac{-y}{x+2}$

Step 3: Find y

Define equation: $-xy - 2y = -4$
Factor y: $y(-x - 2) = -4$
Isolate y: $y = \frac{-4}{-x-2}$
Simplify: $y = \frac{4}{x+2}$

Step 4: Rewrite 1st Derivative

[Algebra] Substitute in y: $y' = \frac{-\frac{4}{x+2} }{x+2}$
[Algebra] Simplify: $y' = \frac{-4}{(x+2)^2}$

Step 5: Differentiate Pt. 2

Find 2nd Derivative

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{0(x+2)^2 - 8 \cdot 2(x + 2) \cdot 1}{[(x + 2)^2]^2}$
[Derivative] Simplify: $y'' = \frac{8}{(x+2)^3}$