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ankoles [38]
3 years ago
15

Why is it mathematically legal to multiply 2 √ 2 by √ 2 √ 2 in order to rationalize the denominator?

Mathematics
1 answer:
Gala2k [10]3 years ago
6 0
Well if you're referring to rationalizing \bf \cfrac{2}{\sqrt{2}}, which simply means, getting rid of the pesky radical at the bottom

well, it boils down to, hmm say... a quantity or even a polynomial, multiplied times 1, is itself, 2*1=2, 3*1 = 3, ducks*1 = ducks, spaghetti * 1 = spaghetti

or whatever * 1 = whatever
and the value of the multiplicand, doesn't change in anyway, is the same thing before and after the multiplication by 1

now....1 can also be a fraction  \bf \cfrac{2}{2}=1\qquad \cfrac{3}{3}=1\qquad \cfrac{1,000,000}{1,000,000}=1
\\\\\\
\cfrac{ducks}{ducks}=1\qquad \cfrac{spaghetti}{spaghetti}=1\qquad \cfrac{cheese}{cheese}=1
\\\\\\
\cfrac{\textit{the quick fox jumped}}{\textit{the quick fox jumped}}=1\qquad \cfrac{whatever}{whatever}=1

so.. when you're doing \bf \cfrac{2}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\iff \cfrac{2}{\sqrt{2}}\cdot1

and the value multiplicand doesn't change in any way

now, try this in your calculator  \bf \cfrac{2}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies \cfrac{2\sqrt{2}}{\sqrt{2^2}}\implies \cfrac{2\sqrt{2}}{2}\implies \sqrt{2}\\\\
-----------------------------\\\\
\textit{check how much is }\cfrac{2}{\sqrt{2}}\textit{ in your calculator}
\\\\\\
\textit{then check how much is }\sqrt{2}\textit{ in it}
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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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<u>Geometry</u>

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Step-by-step explanation:

<u>Step 1: Set up</u>

75 + 120 + 90 + ∠4 = 360

<u>Step 2: Solve</u>

  1. Add:                                                                                                                   285 + ∠4 = 360
  2. [Subtraction Property of Equality] Subtract 285 on both sides:                   ∠4 = 75
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