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RSB [31]
3 years ago
5

 Does somebody knows how to do this?

Mathematics
2 answers:
slava [35]3 years ago
5 0

Answer:

12 cm²

Step-by-step explanation:

Area of rectangle= length ×breadth

Area of triangle= ½ ×base ×height

Area of shaded region

= area of rectangle -area of triangle

= 5(3) -½(2)(3)

= 15 -3

= 12cm²

Nady [450]3 years ago
4 0

Answer:

The answer is 6cm.

Step-by-step explanation:

3×2=6

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Molly is filling bags of marbles. She makes each bag so that 3 out of every 8 marbles are blue. Which equation correctly compare
xeze [42]

Answer:

19

Step-by-step explanation:

Solving,

4x-5 = 27 add five to both sides

4x =32 divide by 4

x = 8 = blue marbles

3x-5 = 19 = red marbles.

5 0
2 years ago
If f(x)=x-6 and g(x)=x1/2(x+3), find g(x) times f(x)
Elden [556K]
To solve this problem you must apply the proccedure shown below:
 1. You have the following functions given in the problem above:
 f(x)=x-6 &#10; and g(x)=x1/2(x+3)=x(x+3)/2<span>
 2. You have that g(x) times f(x) can be written as g(x)*f(x). Therefore, you must multiply f(x) * g(x), as following:
 </span>g(x)*f(x)=(x-6)*x(x+3)/2<span>
 3. Applying the distributive property, you have:
</span> g(x)*f(x)=( x^{3} + 3x^2 - 6x^{2} -18x)/2
 g(x)*f(x)=(x^{3} - 3x^{2} -18x)/2
 The answer is:  g(x)*f(x)=(x^{3} - 3x^{2} -18x)/2
5 0
3 years ago
Please help with 4. And 5
Hoochie [10]
More info please thanks
6 0
4 years ago
The course grade in a statistics class is the average of the scores on five examinations. Suppose that a student's scores on the
nadya68 [22]

Answer:

84 is the highest possible course average

Step-by-step explanation:

Total number of examinations = 5

Average = sum of scores in each examination/total number of examinations

Let the score for the last examination be x.

Average = (66+78+94+83+x)/5 = y

5y = 321+x

x = 5y -321

If y = 6, x = 5×6 -321 =-291.the student cannot score -291

If y = 80, x = 5×80 -321 =79.he can still score higher

If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.

If y= 100

The average cannot be 100 as student cannot score 179(maximum score is 100)

8 0
3 years ago
How do you do this? It's geometry
antiseptic1488 [7]
45.

12/18 = 8/x <=> 2/3 = 8/x <=> x = (3*8)/2 = 12;
7 0
3 years ago
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